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Scilla [17]
3 years ago
10

Please help!?!? needs to show work too.

Physics
1 answer:
ankoles [38]3 years ago
7 0

In order to solve problems like this, you need to know that whenever
there are waves involved ...

          <u>(wavelength) x (frequency)  = speed of the wave </u>.

Both of these problems are about sound, so you'll need to know the speed
of sound.  I'm going to use 340 meters per second. You should look it up to
see if that's a reasonable number.

1). (wavelength) x (frequency)  = speed of the wave

The wavelength is given, and I picked a number for the speed.

         (0.667 m) x (frequency) = (340 m/s)

Divide each side by 0.667 m :    Frequency = (340 m/s) / (0.667 m) = <em>509.7 Hz</em>.


2).  I picked a number for speed, and two frequencies are given.
We have to find the wavelength for each frequency.

<u>20 Hz:</u>
(wavelength) x (frequency)  = speed of the wave

       (wavelength) x (20 Hz) = 340 m/s

Divide each side by  20 Hz:        Wavelength = (340 m/s) / (20 Hz) = <em>17 m</em>

<u>16,000 Hz:</u>
(wavelength) x (frequency)  = speed of the wave

   (wavelength) x (16,000 Hz) = 340 m/s

Divide each side by 16,000 Hz:  Wavelength = (340 m/s)/(16,000 Hz) = <em>2.125 cm </em>


I also want to tell you how much I like the wavy appearance of these
questions about waves in the picture you attached !


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Answer:

Here is the complete question:

https://www.chegg.com/homework-help/questions-and-answers/magnetic-field-372-t-achieved-mit-francis-bitter-national-magnetic-laboratory-find-current-q900632

a) Current for long straight wire  =3.7\ MA

b) Current at the center of the circular coil =2.48\times 10^{5}\ A

c) Current near the center of a solenoid 236.8\ A

Explanation:

⇒ Magnetic Field due to long straight wire is given by (B),where B=\frac{\mu\times I}{2\pi(r) },so\ I=\frac{B\ 2\pi(r)}{\mu}

\mu=4\pi \times 10^{-7}\ \frac{henry}{m}

Plugging the values,

Conversion 1\times 10^6 A = 1\ MA,and 2cm=\frac{2}{100}=0.02\ m

I=\frac{37.2\times \ 2\pi(0.02)}{4\ \pi \times (10^{-7})}=3.7\ MA

⇒Magnetic Field at the center due to circular coil (at center) is given by,B=\frac{\mu\times I (N)}{2(a)}

So I= \frac{2B(a)}{\mu\ N} = \frac{2\times 37.2\times 0.42}{4\pi\times 10^{-7}\times 100}=2.48\time 10{^5}\ A

⇒Magnetic field due to the long solenoid,B=\mu\ nI=\mu (\frac{N}{l})I

Then I=\frac{B}{\mu(\frac{N}{L})} \approx 236.8\A  

So the value of current are  3.7 MA,2.48\times 10^{5} A and 236.8\ A respectively.

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To calculate the initial velocity of the bike, we use the following equation

d=\frac{1}{2} (u+v)t.

or

u=\frac{2d}{t} -v

Here, u is initial velocity, v is final velocity, t is the time and d is the distance covered by bike.

Given, u =7.8 m/s,d= 19 m and t=4.2 s.

Substituting these values in above equation, we get

u = \frac{2 \times 19}{4.2 \ s} -7.8 m/s = 9.05 \ m/s - 7.8 \ m/s \\\\ u= 1.2 m/s.

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3 0
3 years ago
Standing waves can ruin the acoustics of a concert hall if there is excessive reflection of the sound waves that the performers
Dmitrij [34]

Answer:

The answer to the questions is;

In terms of standing waves, the listener moves from a location with high amplitude to one with lower amplitude or vibration (anti-node to node)

The distance 4.1 cm is equivalent to λ/4

Explanation:

For standing waves we have is a stationary wave comprising of two opposite direction moving waves that have equal amplitude and frequency, resulting in the superimposition of the waves. As such certain points are fixed along the wave path that is the peaks amplitude of the wave oscillation is constant at a particular point. A node occurring at a point and an anti-node occurring at another fixed point

When the listener moves 4.1 cm he or she has left the anti-node to the node hence the faintness of the sound

The distance from the node to the anti-node is 1/4 wavelength, or 1/4×λ

Therefore 4.1 cm is λ/4

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