Question

You are trying to climb a castle wall so, from the ground, you throw a hook with a rope attached to it at 24.1 m/s at an angle of 65.0° above the horizontal. If it hits the top of the wall at a speed of 16.3 m/s, how high is the wall?

Answer 1

Answer:

The value is  $h = 13.2 \ m$

Explanation:

From the question we are told that

    The speed of the rope with hook is $u = 24 .1 \ m/s$

     The angle is  $\theta = 65.0^o$

      The speed at which it hits top of the wall is  $v = 16.3 m/s$

Generally from kinematic equation we have that

      $v_y^2 = u_y ^2 + * 2 (-g)* h$

Here h is the height of the wall so

      $[16.3 sin (65)]^2 = [24.1 sin (65)] ^2+ 2 (-9.8)* h$

=>    $h = 13.2 \ m$