Answer:
t₂ = t₁ / 5
Explanation:
Rotational kinematics using: ωf = ωi + αt
Starting from rest and speeding up:
ω₁ = 0 + αt₁ .. Eq1
Starting from ω₁ and slowing to a stop:
0 = ω₁ - 5αt₂
Substituting for ω₁ from Eq 1
0 = αt₁ - 5αt₂
5αt₂ = αt₁
5t₂ = t₁
t₂ = t₁ / 5
They are red because of there pigment called anthocyanins
-90.0 °F = -67 and 7/9 °C
-90.0 °F also = +205.372 K
-5.0 °C = +23 °F
-5.0 °C also = +268.15 K
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Distance of R/2:
Since a conducting sphere is referenced in this situation, all of its charge will be distributed along its SURFACE. Therefore, there is NO enclosed at a distance of R/2 from the center.
Using Gauss's Law:
E = Electric field strength (N/C)
A = Area of Gaussian surface (m²)
Q = Enclosed charge (C)
ε₀ = Permittivity of free space C²/Nm²)
If the enclosed charge is 0, then:
Distance of '2R':
We can once again use Gauss's Law to solve. This time, however, a surface of radius '2R' encloses ALL of the charge of the sphere.
'A' is equivalent to the surface area of a sphere of radius '2R', or:
Substituting this expression back into Gauss's Law:
To simplify:
OR using k = 1/4πε₀: