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Paladinen [302]

3 years ago

6

Help please I don’t get it

1 answer:

vodka [1.7K]3 years ago

5 0

Answer:

$12+\frac{1}{4}\cdot12$ $,$ $12\left(1+\frac{1}{4}\right)$ $and$ $12\cdot\frac{5}{4}$

Step-by-step explanation:

$--------------------------------------------$

$\frac{1}{4}$ $of$ $12$ $is$ $3$

$12+3$ = $15$

$--------------------------------------------$

$12+\frac{1}{4}$ = $12.25$ ✘

$12\cdot\frac{1}{4}$ = $3$ ✘

$12+\frac{1}{4}\cdot12$ = $15$ ✔

$12\left(1+\frac{1}{4}\right)$ = $15$ ✔

$12\cdot\frac{3}{4}$ = $9$ ✘

$12\cdot\frac{5}{4}$ = $15$ ✔

$--------------------------------------------$

<em>Sorry that it took long, really wanted to work hard on this one.</em>

$--------------------------------------------$

<em>Hope this helps! <3</em>

$--------------------------------------------$

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earnstyle [38]

The ratio would be 4 to 1

7 0

4 years ago

Find the length of each side of the triangle determined by the three points P1,P2, and P3. State whether the triangle is an isos

Tanya [424]

Answer:

The triangle is both an Isosceles triangle and a right triangle.

Step-by-step explanation:

Given the vertices of a triangle.

$P_{1} = (- 1, 4)$

$P_{2} = (6, 2)$ and

$P_{3} = (4, - 5)$

We find the distance between all the points to determine the length of each side of the triangle.

Distance between any two points, say, $(x_1, y_1)$ and $(x_2, y_2)$ is:

$\sqrt{\bigg ( \textbf{x}_{\textbf{2}} \hspace{1mm} \textbf{- x}_{\textbf{1}} \bigg )^{\textbf{2}} \textbf{+} \bigg( \textbf{y}_{\textbf{2}} \hspace{1mm} \textbf{- y}_{\textbf{1}} \bigg)^ {\textbf{2}}$

Length between $P_1$ and $P_{2}$ , (Side 1) :

$(x_1, y_1) = (- 1, 4)$ and

$(x_2, y_2) = (6, 2)$

Distance = $\sqrt{\bigg(6 - (-1) \bigg)^{2} \hspace{1mm} + \hspace{1mm} \bigg( 2 - 4 \bigg )^2$

$= \sqrt{7^2 + 2^2}$

$= \sqrt{49 + 4}$

$= \sqrt{\textbf{53}}$

Length of Side 1 = $\sqrt{\textbf{53}}$ units.

Distance between $P_1$ and $P_2$ , (Side 2):

$(x_1, y_1) = (-1, 4)$

$(x_2, y_2) = (4, - 5)$

Distance = $\sqrt{ \bigg( 4 + 1 \bigg)^2 \hspace{1mm} + \bigg( - 5 - 4 \bigg ) ^2$

$= \sqrt{ 25 + 81 }$

$= \sqrt{\textbf{106}}$

Length of Side 2 = $\sqrt{\textbf{106}}$ units.

Distance between $P_2$ and $P_3$ , Side 3 :

$(x_1, y_1) = (4, 5)$

$(x_2, y_2) = (6, 2)$

Distance = $\sqrt{ 2^2 \hspace{1mm} + \hspace{1mm} 7^2}$

$= \sqrt{49 + 4}$

$= \sqrt{\textbf{53}$

Length of Side 3 = $\sqrt{\textbf{53}}$ units.

Note that the length of Side 1 = Length of Side 3.

That means the triangle is Isosceles.

Also, For a triangle to be right angle triangle, using Pythagoras theorem we have:

(Side 1)² + (Side 3)² = (Side 2)²

$\bigg( \sqrt{53} \bigg )^2 \hspace{1mm} + \hspace{1mm} \bigg( \sqrt{53} \bigg)^2 \hspace{1mm} = \hspace{1mm} \bigg ( \sqrt{106} \bigg ) ^2$

i.e, 53 + 53 = 106

Hence, the triangle is a right - angled triangle as well.

7 0

4 years ago

Help pls what is 2*123/56+9=

weeeeeb [17]

Answer:

not sure but can use Calculator

5 0

3 years ago

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9966 [12]

Answer:

im taking the same test lol

Step-by-step explanation:

6 0

3 years ago

If y = -1, what is - 3y - 9 equivalent to?

stiv31 [10]

Answer:

-6

Step-by-step explanation:

Plug in (-1) for y: -3(-1) - 9

Simplify: Negative x Negative = Positive

-3(-1) = 3 so... 3-9

3 - 9 = -6

-3y - 9 is equivalent to -6

5 0

3 years ago

Read 2 more answers