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Paladinen [302]
3 years ago
6

Help please I don’t get it

Mathematics
1 answer:
vodka [1.7K]3 years ago
5 0

Answer:

12+\frac{1}{4}\cdot12 , 12\left(1+\frac{1}{4}\right)  and  12\cdot\frac{5}{4}

Step-by-step explanation:

--------------------------------------------

\frac{1}{4} of 12 is 3

12+3 = 15

--------------------------------------------

12+\frac{1}{4} = 12.25 ✘

12\cdot\frac{1}{4} = 3 ✘

12+\frac{1}{4}\cdot12 = 15 ✔

12\left(1+\frac{1}{4}\right) = 15 ✔

12\cdot\frac{3}{4} = 9 ✘

12\cdot\frac{5}{4} = 15 ✔

--------------------------------------------

<em>Sorry that it took long, really wanted to work hard on this one.</em>

--------------------------------------------

<em>Hope this helps! <3</em>

--------------------------------------------

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Answer:

Answers are 20, 12 and 16

Step-by-step explanation:

Y=4x

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y=4(5)

y=20

for x = 3

y=4(3)

y=12

for x = 4

y=4(4)

y=16

4 0
2 years ago
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A code consists of a single digit number from 0-9 and a letter from the alphabet. What is the probability that the code is 3Z? W
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Jan age is 3 less than the twice triss agethe sum of thier ages is 30
tresset_1 [31]
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Researchers at the Centers for Disease Control and Prevention have been studying the decay pattern of a new virus with a decay r
koban [17]

The Researcher will find 69 viruses, because 231 viruses are decayed in 7 hours, if a virus with a decay rate of 19% per hour and they start with 300 viruses.

Step-by-step explanation:

The given is,

                     A new virus with a decay rate of 19% per hour  

                    They start with 300 viruses

Step:1

                  Formula to calculate the viruses at decay rate,

                                                  y = A(1-r)^{t}............................(1)

                 Where, y - No of viruses after given time

                             A - Viruses at initial stage

                              r - Decay rate

                              t - No. of hours

                 From the given,

                              A = 300

                               r = 19% per hour

                               t = 7 hours

                Equation (1) becomes,

                                            y = 300(1-0.19)^{7}

                                               = 300(0.81)^{7}

                                               = 300(0.228767)

                                               = 68.63

               Viruses of 7 hours ≅ 69 viruses

                                                     ( or )

Step:1

        For 1st hour,

          = (No.of viruses in hour) - (No,of viruses in last hour × Decay rate )

              = (300)-(300 × 0.19)

              = 300 - 57

              = 243

       For 2nd hour,

              = (243)-(243 × 0.19)

              = 243 - 46.17

              = 196.83

      For 3rd hour,

              = (196.83)-(196.83 × 0.19)

              = 196.83 - 37.39

              = 159.4323

       For 4th hour,

              = (159.4323)-(159.4323 × 0.19)

              = 159.4323 - 30.2921

              = 129.1402

      For 5th hour,

              = (129.1402)-(129.1402 × 0.19)

              = 129.1402 - 24.5366

              = 104.6035

     For 6th hour,

              = ( 104.6035)-( 104.6035 × 0.19)

              =  104.6035 - 19.8747

              = 84.7288

     For 7th hour,

              = (84.7288)-(84.7288 × 0.19)

              =  84.7288 - 16.0984

              = 68.63 viruses

Result:

          The Researcher will find 69 viruses, because 231 viruses are decayed in 7 hours, if a virus with a decay rate of 19% per hour and they start with 300 viruses.

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