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sasho [114]
3 years ago
12

Which of the following types of models could be used to represent a cell?

Physics
2 answers:
m_a_m_a [10]3 years ago
6 0
Snansnsnjsjjsncncnfjf
lesya [120]3 years ago
4 0

Answer:

d. all of the above

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A car moves with an initial velocity of 19 m/s due north. (Part A) Find the velocity of the car after 5.6 s if its acceleration
galben [10]

Answer

Assuming

east is the positive x direction

north is the positive y direction

initial velocity , u = 19 j m/s

a) acceleration , a = 1.6 j m/s^2

Using first equation of motion

v = u + a × t

v = 19 + 5.6× 1.6

v = 28 j m/s

the velocity of the car after 5.6 s is 28 m/s north

b)

acceleration , a = -1.5 j m/s^2

Using first equation of motion

v = u + a × t

v = 19 - 5.6 ×1.5

v = 10.6 j m/s

the velocity of the car after 5.6 s is 10.6 m/s north

5 0
3 years ago
If the mass of a material is 46 grams and the volume of the material is 14 cm^3, what would the density of the material be?
umka21 [38]

<u>Answer</u>

3.2857 g/cm³


<u>Explanation</u>

Density of a material is the mass of a unit volume of that material. It's SI unit is Kg/m³ but its has other units like g/cm³.

Density  = mass/volume

             = 46/14

             = 3.2857 g/cm³

3 0
4 years ago
An airplane travels from st louis to portland, oregon in 4.33 hours. if the distance traveled is 2,742 kilometers, what is the a
Makovka662 [10]

Average speed = (total distance covered) / (total time to cover the distance)

                       =  (2,742 km)  /  (4.33 hours)

                       =  (2,742 / 4.33)    km/hr

                       =      633 km/hr        (rounded)
4 0
3 years ago
Read 2 more answers
Incident rays parallel to the axis of a concave mirror reflect parallel to the axis.
coldgirl [10]
No they don't.  Incident rays parallel to the axis of a concave mirror
reflect from the mirror's surface and converge at its focal point.
3 0
3 years ago
A nature photographer is using a camera that has a lens with a focal length of 3.06 cm. The photographer is taking pictures of a
sleet_krkn [62]

Answer:

film is at distance of 3.07 cm from lens

Explanation:

Given data

focal length = 3.06 cm

distance = 10.4 m = 1040 cm

to find out

How far must the lens

solution

we apply here lens formula that is

1/f = 1/p + 1/q

here f = 3.06 and p = 1040 so we find q

1/f = 1/p + 1/q

1/3.06 = 1/1040 + 1/q

1/ q =  0.3258

q = 3.0690 cm

so film is at distance of 3.07 cm from lens

6 0
3 years ago
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