Explanation:
Given that,
Initial speed of the airfield, u = 0
Final speed, v = 27.8 m/s
Acceleration of the airfield, 
Length of the runway, d = 150 m
Let v' is the speed of the airplane to reach the required speed for takeoff. Finding v' using third equation of motion as :
This speed is not enough as the airfield must reach a speed before takeoff of at least 27.8 m/s. Now, the required length of the runways is :
So, the minimum length of the runways is 193.21 meters.
If they both are moving with the same speed and direction
i.e. covering the same distance in the same time interval in the same direction
Answer:
increase
decrease
Explanation:
using formula
Vt=mg/6πηr
so if m increases V increases
r is the denominator so if r increases V decreases
It will be 49 Newtons of force in the down direction. To find the force in newtons, you multiply the mass (5 kg) by the gravity (which if 9.8).
Time = (distance) / (speed)
Time = (150 x 10⁹ m) / (3 x 10⁸ m/s) =
50 x 10¹ sec =
<em>500 sec</em> = 8 min 20 sec
