How many times more gravitational potential energy would the same lander have on top of a 350-m hill on Earth? It would have tim
1 answer:
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Answer:
t = 6.68 seconds
Explanation:
The acceleration of the automobile,
Initial speed of the automobile, u = 91 km/hr = 25.27 m/s
Final speed of the automobile, v = 104 km/hr = 28.88 m/s
Let t is the time taken to accelerate from u to v. It can be calculated as the following formula as :
t = 6.68 seconds
So, the time taken by the automobile to accelerate from u to v is 6.68 seconds. Hence, this is the required solution.
Answer:
<h2>Angular Displacement 6.28 radians</h2>Explanation:
for circular motion we are expected to solve for Angular Displacement it is measured in radian
Measurement of Angular Displacement.
we can measure it using the following relation
∅= s/r
where
s = the distance travelled by the body, and
r = radius of the circle along which it is moving.
given that
circumference c, s= 400 m
r= ?
we have to solve for the radius
we know that circumference
400= 2*3.142*r
400= 6.282*r
divide both sides by 6.284 we have
400/6.284
r= 63.63 m
Angular displcament
∅= 400/63.63
∅= 6.28 radians