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Tcecarenko [31]
3 years ago
12

Can u figure out the surface area and volume i will give brainlest

Mathematics
2 answers:
Mama L [17]3 years ago
5 0

Answer:

Volume: 120

SA: 400

Step-by-step explanation:

Volume = Bh

Volume = (1/2 x b x h) h

Volume = (1/2 x 6 x 4) 10

Volume = 120

SA = 2B + Ph

SA = 2(1/2 x b x h) + (s + s + s)h

SA = 2(1/2 x 6 x 4) + (5 + 5 +6) 10

SA = (24 + 16) 10

SA = 40 x 10

SA = 400

olga55 [171]3 years ago
4 0

Answer:

V:240

S: 400

im think that its right

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Average rate of change help!!
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Given that the function is f(x)=x^{3}-6 x^{2}+4 x+7

We need to determine the average rate of change over the interval 0 \leq x \leq 5

<u>Value of f(x) when x = 0:</u>

Substituting x = 0 in the function f(x)=x^{3}-6 x^{2}+4 x+7, we have;

f(0)=(0)^{3}-6 (0)^{2}+4 (0)+7

f(0)=0-0+0+7

f(0)=7

Thus, the value of f(0) is 7.

<u>Value of f(x) when x = 5:</u>

Substituting x = 5 in the function f(x)=x^{3}-6 x^{2}+4 x+7, we have;

f(5)=(5)^{3}-6 (5)^{2}+4 (5)+7

f(5)=125-150+20+7

f(5)=2

Thus, the value of f(5) is 2.

<u>Average rate of change:</u>

The average rate of change can be determined using the formula,

Rate \ of \ change=\frac{f(b)-f(a)}{b-a}

where a=0 and b=5

Thus, we have;

Rate \ of \ change=\frac{f(5)-f(0)}{5-0}

Rate \ of \ change=\frac{2-7}{5-0}

Rate \ of \ change=\frac{-5}{5}

Rate \ of \ change=-1

Thus, the average rate of change over the interval 0 \leq x \leq 5 is -1.

3 0
3 years ago
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Aleksandr-060686 [28]

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Answer:

m = -1

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Hope this helps!

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