Jot down the formula of the ionic compound. Let's say the ionic compound you're working with is NaCl.
Write the name of the metal.
Add the name of the non-metal with an –ide ending.
Combine the cation and anion names.
Practice naming more simple ionic compounds.
The model of the solar system is way smaller than the real object. The model of sub-atomic particles in a atom is way larger than the real object.
power = work/time
watt = joule/sec
a) power = 0.10 watt = 0.1joules/sec
work = power * time
= 0.10 * 1 =0.1joules
work is northing but energy
therefore energy is 0.1joules
according to planks quantum theory E = nhν where nis the no. of photons ; h is planks constant; ν isfrequency
hence, n = E/hν
or n = Eλ/hc (ν = c/λ)
n = (0.1*700*10^-9)/6.625*10^-34*3*10^8 = 0.3522*10^18photons
b) similar to the above calculation
here E = 1.0joules
n = (1.0*700*10^-9)/6.625*10^-34*3*10^8 = 0.3522*10^17photons
Answer:
4 M
Explanation:
Molarity can be represented by the following ratio:
Molarity = moles / volume (L)
Since you have been given both the mass and volume, you can plug the values into the equation and solve for molarity.
Molarity = moles / volumes
Molarity = 2.0 moles / 0.50 L
Molarity = 4 M
Answers:
1) <span>Breaking Solvent-Solvent Attractions is an Endothermic Process.
2) </span><span>Breaking Solute-Solute Attractions is an Endothermic Process.
3) </span><span>Forming Solute-Solvent Attractions is an Exothermic Process.
Explanation:
When a solute is dissolved in solvent it either releases heat or absorbs heat depending upon the the interactions broken and interactions formed. At first, the solvent solvent interactions are broken , this process requires heat which is provided either from external source or is provided by the forming of solute solvent bond forming process which is exothermic.
When the solvent molecules get apart the solute particles enter to form interactions with elimination of heat. So, if the heat required to break solvent solvent interactions is greater than the heat provided by solute solvent interactions formation then the solute will not dissolve at room temperature and vice versa.</span>
