Answer:
What is the empirical formula of the compound?
Explanation:
When the relative masses of elements in a hydrocarbon are given, it is possible to use this information to obtain the empirical formula by dividing the given masses of each element by the relative atomic masses of the element. The lowest ratio is now used to divide through to obtain the empirical formula of the compound.
The empirical formula only shows that ratio of atoms of each element present in the compound. From the information provided, the empirical formula of the compound is CH2. Hence the answer.
Answer:
This study is an overview of previous studies on lime (quick and hydrated) -treated soil. Lime is the oldest traditional stabilizer used for soil stabilization. The mechanism of soil-lime treatment involves cation exchange, which leads to the flocculation and agglomeration of soil particles. The high pH environment then causes a pozzolanic reaction between the free Ca+2 cations and the dissolved silica and alumina. Lime-treated soil effectively increases the strength, durability and workability of the soil. Such treatment also improves soil compressibility. A fluctuation behavior was observed on the influence of lime on soil permeability. However, the factors affecting the permeability of the soil-lime mixture should be extensively studied. Nonetheless, lime treatment has a number of inherent disadvantages, such as carbonation, sulfate attack and environment impact. Magnesium oxide/hydroxide are thus proposed as a suitable alternative stabilizer to overcome at least some of the disadvantages of using lime in soil stabilization.
Explanation:
Actually I have a pdf on it to explain more if you want but how to get it to you is the issue. well I'm guessing the one I've put out should be very much okay, I hope so .
Answer:
Noble Gases
Explanation:It's not on there but Noble gases is the least reactive element because it has 8 electrons and their outer energy is full.
Explanation:
no. of molea of Ca(NO3)2 = given mass/molar mass
no. of moles= 92/ 164 = 0.56 mol
formula=
Molarity = moles of solute /solution in litres
Molarity = 0.56/ 0.4
=1.4 M
hope it helped!