<h3>
Answer:</h3>
1379.4 Joules
<h3>
Explanation:</h3>
- The quantity of heat is calculated multiplying the mass of a substance by heat capacity and the change in temperature.
Therefore;
Quantity of heat = Mass × specific heat capacity × Change in temperature
Q = mcΔT
In this case;
The substance dissolved in water gained heat while water lost heat energy.
Thus, Heat gained by the substance = heat lost by water
Heat associated with the water
Mass of water = 75 g
Change in temperature = 4.4°C
Specific heat capacity = 4.18 J/g·⁰C
Heat = mcΔT
= 75 g × 4.18 J/g·⁰C × 4.4 °C
=1379.4 Joules
Answer:
A cation has more protons than electrons, consequently giving it a net positive charge. For a cation to form, one or more electrons must be lost, typically pulled away by atoms with a stronger affinity for them.
Were i found my answer: Cation vs Anion: Definition, Chart and the Periodic Table
Explanation:
The chemical formula of a compound express the atoms by which the molecule is formed and the ratio of the atoms in which they are combined.
The space filling model of a compound describe the electron density in the compound of each atom.
The ball and stick arrangement of a compound describe the way in which the molecules are present in three dimensions.
The structural formula state the number of atoms present in the molecule, the type of element or atom present in the molecule and the way in which they are arranged closely which is the bond.
Thus only the structural formula only will cover all the options as stated.
Answer:
could the answer be boil the water away?
Explanation:
if the water gets boiled and evaporates, than you are left with the solids
2Ca + O2 = 2CaO
First, determine which is the excess reactant
72.5 g Ca (1 mol) =1.8089725036
(40.078 g)
65 g O2 (1 mol) =2.0313769611
(15.999g × 2)
Since the ratio of to O2 is 2:1 in the balanced reaction, divide Ca's molar mass by 2 to get 0.9044862518. this isn't necessary because Ca is already obviously the limiting reactant. therefore, O2 is the excess reactant.
Now do the stoichiometry
72.5 g Ca (1 mol Ca) (1 mol O2)
(40.078 g Ca)(2 mol Ca)(31.998g O2)
=0.0282669621 g of O2 left over
