1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
galina1969 [7]
3 years ago
14

Can someone help me? 8th grade math

Mathematics
1 answer:
Svetllana [295]3 years ago
3 0

9514 1404 393

Answer:

  a. 5^-3

  b. 14^18

  c. 8^9

  d. 16^3

  e. 21^-18

Step-by-step explanation:

The applicable rules of exponents are ...

  (a^b)(a^c) = a^(b+c)

  (a^b)/(a^c) = a^(b-c)

  (a^b)^c = a^(bc)

__

a) 5^(3-6) = 5^-3

b) 14^(3·6) = 14^18

c) 8^(3+6) = 8^9

d) 16^(6-3) = 16^3

e) 21^(3(-6)) = 21^-18

You might be interested in
If 4x is one factor of 4x^2-12x, what is the other factor?
Zepler [3.9K]
If you factor 4x²-12x, you can divide 4x from each term.

4x² ÷ 4x = x
-12x ÷ 4x = -3

Therefore, the other term becomes (x-3) because 4x(x-3) = 4x²-12x
4 0
3 years ago
A rhombus and a triangle are equal in areas. if the base and height of the triangle are 24.8 cm and 5.5 cm respectively and the
ipn [44]

<h2>Given :-</h2>

  • Area of Rhombus = Area of Triangle

  • Base and Height of Triangle is 24.8 cm and 5.5 cm respectively .

  • Length of one diagonal of the rhombus is 22 cm .

<h2>To Find :-</h2>

  • Length of other Diagonal

<h2>Solution :-</h2>

As we know that

Area of triangle = ½ × Base × Height

  • Area = ½ × 24.8 × 5.5
  • Area = 1 × 12.4 × 5.5
  • Area = 12.4 × 5.5
  • Area = 68.2 cm²
<h3 /><h3>Now,</h3><h3 />

Area of rhombus = ½ × D1 × D2

  • 68.2 = ½ × 22 × D2
  • 68.2 × 2 = 22 × D2
  • 136.4 = 22 × D2
  • 136.4/22 = D2
  • 6.2 = D2
  • D2=6.2

<h2>Hence :-</h2>

<h3>Other Diagonal is 6.2 cm.</h3>

\begin{gathered} \\ \end{gathered}

7 0
3 years ago
1) A light bulb producing company states that its lights will last an average of 1200 hours with a standard deviation of 200 hou
Ronch [10]

The mean ( average ) is given as 1200 hours.

The standard deviation is 200, sample size is 100.

Find the standard error:

√(200^2 / 100) = 20

Now calculate the confidence interval. For 95% the Z number is 1.96

Multiply Z by the standard error:

1.96 x 20 =39.2

Now find the range that the mean should be within:

1200 - 39.2 = 1160.8

1200 + 39.2 = 1239.2

The samples should be between 1160.8 and 1239.2 for a 95% confidence interval.

Since the average was 1050, which is below 1160.8 the bulbs are not in compliance.

4 0
4 years ago
Which is the ordered pair of represents point d
Tanya [424]

Answer:

D. (3,2)

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Please help me I will give brainliest
Scrat [10]

Answer:

Hm?

Step-by-step explanation:

Why should i

8 0
3 years ago
Other questions:
  • The average annual salary of the employees of a company in the year 2005 was ninety thousand dollars. It increased by the same f
    15·1 answer
  • I'm not the greatest at math so I got stuck<br> x=<br><br> 80<br> 90<br> 100
    13·1 answer
  • The total points earned in the football game was 42. The Falcons earned 2/3 of that score. How many points did the other team sc
    5·1 answer
  • The cost of 100 mechanical pencils is $42.60. The cost of 100 colored pencils is $32.60. How much more does one mechanical penci
    12·2 answers
  • The median AM of triangle ∆ABC is half the length of the side towards which it is drawn, BC . Prove that triangle ∆ABC is a righ
    13·1 answer
  • Rewrite 1/2 * 1/2 * 1/2 * 1/2 as an exponential expression with a base of 2.
    11·2 answers
  • What is the probability of rolling an even number and landing on a letter thats not an s
    13·1 answer
  • This was very hard for me please help thanks.​
    8·1 answer
  • List on new car costume $20,000 the sale tax is 7% how much does the total cost is​
    5·2 answers
  • 3/4 of Dave's wall is painted blue. 1/2 of the blue wall has posters on it. What fraction of the entire wall has posters on it?
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!