Astronomers deal with objects in space, so it's most likely they would use geometry to determine how far they are, how big they are, etc.
Have a nice day! :)
(1,-10)
the 10 must be negative
reason why the others dont work:
(1,10) too positive, the other two start negative, no way is it going to be way up here
(10,1) still too high
(-1,10) then again, too high
Equation of a circle is:
<span>(x−h<span>)2</span>+(y−k<span>)2</span>=<span>r2</span></span>
h is the x-coordinate of the center and k is the y-coordinate of the center. Even though the formula has minus signs, those are positive numbers. If there were plus signs in there, the numbers h and k would actually be negative. Now since you're centered at the origin, that means h and k are 0, so you'd just have this:
<span><span>x2</span>+<span>y2</span>=<span>r2</span></span><span>
Now since your radius is 7, just square it and replace r^2 woth that value :)</span>
Let us model this problem with a polynomial function.
Let x = day number (1,2,3,4, ...)
Let y = number of creatures colled on day x.
Because we have 5 data points, we shall use a 4th order polynomial of the form
y = a₁x⁴ + a₂x³ + a₃x² + a₄x + a₅
Substitute x=1,2, ..., 5 into y(x) to obtain the matrix equation
| 1 1 1 1 1 | | a₁ | | 42 |
| 2⁴ 2³ 2² 2¹ 2⁰ | | a₂ | | 26 |
| 3⁴ 3³ 3² 3¹ 3⁰ | | a₃ | = | 61 |
| 4⁴ 4³ 4² 4¹ 4⁰ | | a₄ | | 65 |
| 5⁴ 5³ 5² 5¹ 5⁰ | | a₅ | | 56 |
When this matrix equation is solved in the calculator, we obtain
a₁ = 4.1667
a₂ = -55.3333
a₃ = 253.3333
a₄ = -451.1667
a₅ = 291.0000
Test the solution.
y(1) = 42
y(2) = 26
y(3) = 61
y(4) = 65
y(5) = 56
The average for 5 days is (42+26+61+65+56)/5 = 50.
If Kathy collected 53 creatures instead of 56 on day 5, the average becomes
(42+26+61+65+53)/5 = 49.4.
Now predict values for days 5,7,8.
y(6) = 152
y(7) = 571
y(8) = 1631
20 and 45x
We look for a number that can go into both numbers.
5 into 20 is 4 and 5 into 45x is 9x.
5: 20 45x
4 9x
So no other number can go into 4 and 9x again.
So the GCF of 20 and 45x is 5.
Hope this explains it.
