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3 years ago

Pls help!! i don’t understand what i am supposed to do.

Physics

1 answer:

liq [111]3 years ago

7 0

Well, my German isn't as sharp as it used to be, but it looks like you're supposed to use the symbols at the top and draw two circuits ... one where the switch is closed and the light is shining, the other where the switch is open and the light is out.

That should be pretty easy for you. Just hook up one battery, one switch, and one light, all in series. Then opening and closing the switch makes the light go on and off.

You might be interested in

Provide three examples of situations in which mass is the main factor determining an object's momentum

Ratling [72]

The three examples of situations in which mass is the main factor determining an object's momentum are, a moving truck, a moving trailer and a rolling block.

<h3>What is momentum?</h3>

Momentum is the product of mass and velocity of an object

P = mv

where;

m is the mass of the object
v is the velocity of the object

The three examples of situations in which mass is the main factor determining an object's momentum is below;

A moving truck.
A moving trailer.
A rolling block.

The three examples given above shows three objects with heavy mass.

Learn more about momentum here: brainly.com/question/7538238

3 0

3 years ago

A 2 kg object is subjected to three forces that give it an acceleration −→a = −(8.00m/s^2)ˆi + (6.00m/s^2)ˆj. If two of the thre

Angelina_Jolie [31]

Answer:

$\vec{F_3}=(-34.0N)\hat{i}+(-12.0N)\hat{j}$

Explanation:

You have three forces F1, F2 an F3 that produce the following acceleration:

a = −(8.00m/s^2)ˆi + (6.00m/s^2)ˆj

you know that force F1 and F2 are:

F1 = (30.0N)ˆi + (16.0N)ˆj

F2 = −(12.0N)ˆi + (8.00N)ˆj

and the force F3 is unknown:

F3 = F3x ˆi + F3y ˆj

The second Newton law is given by the following equation:

$\vec{F}=m\vec{a}$

F: the total force = F1 +F2 + F3

m: mass of the object = 2 kg

By the properties of vectors you have:

$\vec{F_1}+\vec{F_2}+\vec{F_3}=m\vec{a}\\\\(30.0-12.0+F_{3x})N\hat{i}+(16.0+8.00+F_{3y})N\hat{j}=(2.0kg)[(-8.00m/s^2)\hat{i}+(6.00m/s^2)\hat{j}]\\\\(18.0+F_{3x})N\hat{i}+(24.0+F_{3y})\hat{j}=(-16.00N)\hat{i}+(12.0N)\hat{j}$

Both x and y component must be equal in the previous equality, then you have:

$18.0N+F_{3x}=-16.00N\\\\F_{3x}=-34.00N\\\\24.0N+F_{3y}=12.0N\\\\F_{3y}=-12.00N$

Hence, the vector F3 is:

$\vec{F_3}=(-34.0N)\hat{i}+(-12.0N)\hat{j}$

7 0

4 years ago

A student walks 144 m west, and then turns around and walks 89 m east If this takes place in a 7.5-minute interval, what is the

Darina [25.2K]

The average speed is 0.517 m/s

The average velocity is 0.12 m/s west

<u>Explanation:</u>

When dividing the total distance covered by object by time, we get the value for average speed.

$\text { speed }=\frac{\text {distance}}{\text {time}}$

Calculate the distance without consideration of motion’s direction. So, the distance walks 144 m first, and then another 89 m, so the total distance covered is

d = 144 + 89 = 233 meters

Given t = 7.5 minutes. Convert minute into seconds,

$7.5 \times 60=450 \text { seconds }$

So, the average speed can be calculates as below,

$\text { speed }=\frac{233}{450}=0.517 \mathrm{m} / \mathrm{s}$

When dividing the object’s displacement by time taken, we can calculate average velocity.

$\text {velocity}=\frac{\text {displacement}}{\text {time}}$

In given case, the students walks 144 m west first, and then 89 m east. The displacement is the distance in a straight line between the initial and final position: therefore, in this case, the displacement is

d = 144 (west) - 89 (east) = 55 m (west)

The time taken is t = 450 s

So, the average velocity is

$\text {velocity}=\frac{55}{450}=0.12 \mathrm{m} / \mathrm{s}$

And the direction is west (the same as the displacement).

8 0

4 years ago

Which factors affect the gravitational force between objects? Check all that apply.

drek231 [11]

Explanation:

distance between both objects and masses of the objects

4 0

3 years ago

Read 2 more answers

HURRY

motikmotik

Answer:

in the direction opposite to electric field.

Explanation:

Force on a charged particle

due to electric field

is given by

→

−

0.06

200

−

12 N

Here negative indicates that force is in the direction opposite to electric field.

6 0

2 years ago