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RideAnS [48]
2 years ago
5

How many grams of sodium carbonate (Na2CO3) are needed to produce 6.78

Chemistry
1 answer:
olya-2409 [2.1K]2 years ago
7 0

Answer:

359.3g of Na₂CO₃ are required

Explanation:

When sodium carbonate, Na₂CO₃ reacts with HCl, NaCl and H₂O are produced as follows:

Na₂CO₃ + 2HCl → 2NaCl + CO₂ + H₂O

<em>Where 1 mole of sodium carbonate produce 2 moles of NaCl</em>

<em />

To solve this question, we must find the moles of sodium carbonate required to produce the 6.78 moles of NaCl. With this mass and the molar mass we can find the mass of sodium carbonate as follows:

<em>Moles Na₂CO₃:</em>

6.78 moles NaCl * (1mol Na₂CO₃ / 2mol NaCl) = 3.39 moles Na₂CO₃

<em>Mass Na₂CO₃ -Molar mass: 105.99g/mol:</em>

3.39 moles Na₂CO₃ * (105.99g / mol) =

<h3>359.3g of Na₂CO₃ are required</h3>
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If the gas in the piston above has a volume of 20.0 L at a temperature of 25 C what is the volume of that gas when it is heated
dexar [7]

Answer:

15.98 L

Explanation:

First, you need to find T1, T2, V1 and V2.

T1 = 25 C = 298.15 K (25C + 273.15K)

T2 = 100 C = 373.15 K (100C + 273.15K)

V1 = 20. L

V2 = ? (we are trying to find)

Next, rearrange to fit the formula

V2 = V1 x T1 / T2

Next, fill in with our numbers

V2 = 20. L x 298.15 K / 373.15 K

Do the math and you should get...

15.98 L

- If you need more help or futher explanation please let me know. I would be glad to help!

8 0
3 years ago
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When an object is lifted 10 feet off the ground, it gains a certain amount of potential energy. If the same object is lifted 30
Elden [556K]

Answer: 3 times as much the potential energy

Explanation:

Potential energy is the energy possessed by an object by virtue of its position.

P.E=m\times g\times h

m= mass of object

g = acceleration due to gravity

h = height of an object  

When same object with same is lifted from 10 feet to 30 feet. The height has increased 3 times , thus the potential energy will also get 3 times as much.

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Functions of the following ingredients in the production of dairy products.ii. Enzyme in cheese​
Serjik [45]

Answer:

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3 years ago
Find the force it would take to accelerate an 800-kg car at a rate of 5m/s2.
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Force=800•5

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3 0
2 years ago
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PLEASE HELP WITH THESE TWO QUESTIONS
adelina 88 [10]

1. Q=112.8 kJ

2. Q=5.01 kJ

<h3>Further explanation</h3>

The heat required for phase change :

  • melting/freezing :

Q = mLf

Lf=latent heat of fusion

  • vaporization/condensation

Q = mLv

Lv=latent heat of vaporization

1.

m=50 g=0.05 kg

Lv (water) = 2256 kJ/kg

\tt Q=0.05\times 2256=112.8~kJ

2.

m=15 g=0.015 kg

Lf for water = 334 kj/kg

\tt Q=0.015\times 334=5.01~kJ

3 0
2 years ago
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