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makkiz [27]
2 years ago
8

How does electroplating happen?

Chemistry
2 answers:
Genrish500 [490]2 years ago
4 0

Answer:

im just doing this for points loooool but yes the answer on a p e x is b, thank you :))

Natalka [10]2 years ago
3 0

Answer:

B

Explanation:

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What is the solution of Ag + Cu2+ --> ?
Leviafan [203]

Explanation:

b I dont really know okau

5 0
2 years ago
What is the molecular formula for water?
Alexxandr [17]

Answer:

H2O

Explanation:

There are 2 hydrogen atoms and 1 oxygen atom

5 0
2 years ago
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An unknown compound, X is thought to have a carboxyl group with a pKa of 2.0 and another ionizable group with a pKa between 5 an
Westkost [7]

Answer:

7.3

Explanation:

By Henderson Hasselbalch equation we can calculate the pH or the pOH of a solution by its pKa. Remember that pH = -log[H^{+}], and pKa = -logKa. Ka is the equilibrium constant of the acid.

Henderson Hasselbalch equation :

pH = pKa - log \frac{[HA]}{[A^{-}]}

Where [HA] is the concentration of the acid, and [A^{-}] is the concentration of the anion which forms the acid.

So, acid X, has two ionic forms, the carboxyl group and the other one. First, we have 0.1 mol/L of the acid, in 100 mL, so the number of moles of X

n1 = (0.1 mol/L)x(0.1 L) = 0.01 mol

When it dissociates, it forms 0.005 mol of the carboxyl group and 0.005 mol of the other group. Assuming same  stoichiometry.

Adding NaOH, with 0.1 mol/L and 75 mL, the number of moles of OH^- will be

n2 = (0.1 mol/L)x(0.075 L) = 0.0075 mol

So, the 0.0075 mol of OH^- reacts with 0.005 mol of carboxyl, remaining 0.0025 mol of OH^-, which will react with the 0.005 mol of the other group. So, it will remain 0.0025 mol of the other group.

The final volume of the solution will be 175 mL, but both concentrations (the acid form and ionic form) have the same volume, so we can use the number of mol in the equation.

Note that, the number of moles of the acid form is still 0.01 mol because it doesn't react!

So,

6.72 = pKa - log \frac{0.01}{0.0025}

6.72 = pKa - log 4

pKa - log4 = 6.72

pKa = 6.72 + log4

pKa = 6.72 + 0.6

pKa = 7.3

8 0
3 years ago
A volume of 25.36 ± 0.05 mL 25.36±0.05 mL of HNO 3 HNO3 solution was required for complete reaction with 0.8311 ± 0.0007 g 0.831
Sholpan [36]

Answer:

MOLARITY= 0.3092mol/l

ABSOLUTE UNCERTAINTY= 0.000873

Explanation:

The equation of reaction is

2HNO3 + Na2CO3 ⟶ 2NaNO3 + H2O + CO2.

QUESTION1: CALCULATION FOR MOLARITY;

Molarity= gram mole of solute ÷ liters of solution

Where;

Mole of solute= mass ÷ molar mass

Therefore;

Mole of solute= 0.8311g ÷ 105.988g/mol= 0.0078515mol

MOLARITY= 0.0078415mol ÷ 25.36ml = 0.0003092mol/ml = 0.3092mol/l

This is the Molarity of the solution

QUESTION2: CALCULATION FOR ABSOLUTE UNCERTAINTY;

Uncertainty (u) =√([0.05 ÷ 25.36]^2 + [0.001 ÷ 105.988]^2 + [0.0007 ÷ 0.8311]^2) × Molarity

Solving brackets gives

(0.00197161+0.00000943503+0.00084226) ×Molarity

Adding up gives

0.002823×Molarity

Therefore;

ABSOLUTE UNCERTAINTY= 0.002823×0.3092= 0.000873

5 0
3 years ago
PLEASE HELP!!!! The energy diagram shows the change in energy during a chemical reaction. Which statement best describes the tot
eimsori [14]

Answer: B

Explanation:

6 0
2 years ago
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