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makkiz [27]
3 years ago
8

How does electroplating happen?

Chemistry
2 answers:
Genrish500 [490]3 years ago
4 0

Answer:

im just doing this for points loooool but yes the answer on a p e x is b, thank you :))

Natalka [10]3 years ago
3 0

Answer:

B

Explanation:

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How long will it take for a 40.0 gram sample of I-131 (half-life = 8.4 days) to decay to 1/16 its original mass?
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Answer:

42 days

Explanation:

Half life = 8.4 days

Starting mass = 40.0 g

Time = ?

Final Mass = 1/16 * 40 = 2.5 g

First Half life;

Remaining mass = 40 / 2 = 20g

Second Half life;

Remaining mass = 20 / 2 = 10g

Third Half life;

Remaining mass = 10 / 2 = 5g

Fourth Half life;

Remaining mass = 5 / 2 = 2.5g

Time = Number of half lives * Duration of half life = 5 * 8.4 = 42 days

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A student wants to prepare 1.00 L of a 1.00 M solution of NaOH (molar mass 40.00 g/mol). If solid NaOH is available, how would t
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Explanation:

1)

Molarity=\frac{\text{Mass of substance}}{\text{Molar mass of substance}\times \text{Volume of solution(L)}}

Mass of NaOH = m

MOlar mass of NaOH = 40 g/mol

Volume of NaOH solution = 1.00 L

Molarity of the solution= 1.00 M

1.00 M=\frac{m}{40 g/mol\times 1.00 L}

m=1.00 M\times 40 g/mol\times 1.00 L = 40. g

A student can prepare the solution by dissolving the 40. grams of NaOH in is small volume of water and making that whole volume of solution to volume of 1 L.

Upto two significant figures mass should be determined.

2)

M_1V_1=M_2V_2 (dilution equation)

Molarity of the NaOH solution = M_1=2.00 M

Volume of the solution = V_1=?

Molarity of the NaOH solution after dilution = M_2=1.00 M

Volume of NaOH solution after dilution= V_2=1 L

M_1V_1=M_2V_2

V_1=\frac{1.00 M\times 1.00 L}{2.00 M}=0.500 L

A student can prepare NaOH solution of 1.00 M by diluting the 0.500 L of 2.00 M solution of NaOH with water to 1.00 L volume.

Upto three significant figures volume should be determined.

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