Question

Watch the video that shows using the dilution method to make a solution of known concentration. Note that while the video shows the use of a beaker, in the lab we typically use a volumetric flask to make the diluted solution. The stock solution of KMnO4 has a concentration of 2.6 × 10-4 M. The pipette has a volume of 10.0 mL. What is the amount of KMnO4 delivered to the solution, in moles

Answer 1

Answer:

$2.6\times 10^{-6}\ moles$

Explanation:

Considering:

$Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}$

Or,

$Moles =Molarity \times {Volume\ of\ the\ solution}$

Given :

For potassium permanganate :

Molarity = $2.6\times 10^{-4}\ M$

Volume = 10.0 mL

The conversion of mL to L is shown below:

1 mL = 10⁻³ L

Thus, volume = 10.0×10⁻³ L

Thus, moles of potassium sulfate :

$Moles=2.6\times 10^{-4} \times {10.0\times 10^{-3}}\ moles$

Moles of potassium permanganate = $2.6\times 10^{-6}\ moles$