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3 years ago

Could you please help me with finding the circumference? An explanation to go with it would be great!

Mathematics

1 answer:

Naddik [55]3 years ago

4 0

Step-by-step explanation:

37,7m, π*(r*2)

r*2 is diameter it's kinda ez , just put 37,7m and ur done

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PLEASE HELP

Kruka [31]

Answer:

17 inches

Step-by-step expl

8 0

3 years ago

Read 2 more answers

The diagram represents a dilation with a center at P. If the scale factor of e dilation is K, which statement about the diagram

boyakko [2]

Answer:

C is correct. If the scale factor is greater than 1, the image is an enlargement. The segment UT could be an enlargement of the segment ST.

Step-by-step explanation:

A. If > 1, then the image of could be .

B. If 0 < < 1, then the image of could be . ( If the scale factor is between 0 and 1, the image is a reduction )

C. If > 1, then the image of could be .

D.If = 2, then the image of is itself.

A is not correct. If the scale factor is between 0 and 1, the image is a reduction.

B is not correct. If the scale factor is between 0 and 1, the image is a reduction.

C is correct. If the scale factor is greater than 1, the image is an enlargement.

D is not correct. If the scale factor is 1, the figure and the image are congruent.

8 0

3 years ago

Given the preimage and image,find the dilation scale factor.

Oliga [24]

Answer:

The dilation scale factor is $\frac{1}{2}$ .

Step-by-step explanation:

The image is the dilated form of its preimage if and only if the following conditions are observed:

1) $K' = \alpha_{1} \cdot K$

2) $T' = \alpha_{2} \cdot T$

3) $P' = \alpha_{3} \cdot P$

4) $J' = \alpha_{4} \cdot J$

5) $\alpha_{1} = \alpha_{2} = \alpha_{3} = \alpha_{4}$

If we know that $K = (2, 0)$ , $K' = (1, 0)$ , $T = (3, 0)$ , $T' = (1.5,0)$ , $P = (1, 5)$ , $P' = (0.5, 2.5)$ , $J = (0, 3)$ and $J' = (0, 1.5)$ , then the coefficients are, respectively:

$\alpha_{1} = \frac{1}{2}$ , $\alpha_{2} = \frac{1}{2}$ , $\alpha_{3} = \frac{1}{2}$ , $\alpha_{4} = \frac{1}{2}$

As $\alpha_{1} = \alpha_{2} = \alpha_{3} = \alpha_{4}$ , we conclude that the dilation scale factor applied in the preimage is equal to $\frac{1}{2}$ .

7 0

3 years ago

What is the mean absolute deviation of the following data set

tatuchka [14]

Answer:

4.32

Step-by-step explanation:

First, we have to find the mean of the data set.

16, 11, 9, 12, 11, 10, 10, 8, 15, 0, 2, 15, 14, 7, 11, 5, 14, 20, 3, 11, 13, 7, 0, 5, 21 all added together equals 250. 250 divided by 25 = 10. So 10 is the mean.

Now we have to find the absolute distances of each number from the mean.

16 - 10 = 6... 11 - 10 = 1... so on, giving us this -->

6, 1, 1, 2, 1, 0, 0, 2, 5, 10, 8, 5, 4, 3, 1, 5, 4, 10, 7, 1, 3, 3, 10, 5, 11

Finally, we have to find the mean of the distances (which is done by adding all the numbers above and dividing the sum by the number of values there are).

108 divided by 25 = 4.32.

So, 4.32 is the mean absolute deviation (MAD) of the following data set.

4 0

3 years ago

Can anyone help me find the area of these two pls ?

Rasek [7]

13: 72.25
14: 52
For 14, you need to split the figure into a triangle and rectangle.

5 0

2 years ago