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Ksju [112]
3 years ago
8

The table below lists the properties of a metallic element. A table with 1 column titled property with entries shiny, silver col

ored, forms +1 and +2 ions, compound with sulfur is bright red. Where on the periodic table would this element most likely be found? Group 1 Group 2 Group 12 Group 13
Chemistry
2 answers:
Sav [38]3 years ago
3 0

Answer:

Group 2

Explanation:

Group 12 and 13 is incorrect because they're are most likely to gain electrons making it a negative ion. even if it loses electrons it will most likely lose more than one or two. Group 1 is incorrect because it can not form a +2 ion because it has only one electron to begin with. Therefore group 2 is correct.

coldgirl [10]3 years ago
3 0

Answer:

Group 2

Explanation:

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Why does a high temperature have to be used to weld pieces of metal together
bazaltina [42]

because of the metling point of metals, it is difficult to just simply put metal together and have them to stay together without any type of glue or epoxy based creams.

wielding is used to melt the surface or even change the compound completely so they are able to combine with other metals.

same thing with atoms, you need a lot of heat, and speed to simply make salt or even copper because of the elements not really being favorable of each other.

8 0
3 years ago
Stu Dent has finished his titration, and he comes to you for help with the calculations. He tells you that 20.00 mL of unknown c
Alexus [3.1K]

Answer:

0.3229 M HBr(aq)

0.08436M H₂SO₄(aq)

Explanation:

<em>Stu Dent has finished his titration, and he comes to you for help with the calculations. He tells you that 20.00 mL of unknown concentration HBr(aq) required 18.45 mL of 0.3500 M NaOH(aq) to neutralize it, to the point where thymol blue indicator changed from pale yellow to very pale blue. Calculate the concentration (molarity) of Stu's HBr(aq) sample.</em>

<em />

Let's consider the balanced equation for the reaction between HBr(aq) and NaOH(aq).

NaOH(aq) + HBr(aq) ⇄ NaBr(aq) + H₂O(l)

When the neutralization is complete, all the HBr present reacts with NaOH in a 1:1 molar ratio.

18.45 \times 10^{-3} L NaOH.\frac{0.3500molNaOH}{1LNaOH} .\frac{1molHBr}{1molNaOH} .\frac{1}{20.00 \times 10^{-3} LHBr} =\frac{0.3229molHBr}{1LHBr} =0.3229M

<em>Kemmi Major also does a titration. She measures 25.00 mL of unknown concentration H₂SO₄(aq) and titrates it with 0.1000 M NaOH(aq). When she has added 42.18 mL of the base, her phenolphthalein indicator turns light pink. What is the concentration (molarity) of Kemmi's H₂SO₄(aq) sample?</em>

<em />

Let's consider the balanced equation for the reaction between H₂SO₄(aq) and NaOH(aq).

2 NaOH(aq) + H₂SO₄(aq) ⇄ Na₂SO₄(aq) + 2 H₂O(l)

When the neutralization is complete, all the H₂SO₄ present reacts with NaOH in a 1:2 molar ratio.

42.18 \times 10^{-3} LNaOH.\frac{0.1000molNaOH}{1LNaOH} .\frac{1molH_{2}SO_{4}}{2molNaOH} .\frac{1}{25.00\times 10^{-3}LH_{2}SO_{4}} =\frac{0.08436molH_{2}SO_{4}}{1LH_{2}SO_{4}} =0.08436M

6 0
3 years ago
exothermic reaction in which the reaction releases energy as heat. 4. How would the reaction would change if you added 2 g of st
Margaret [11]

Answer:

Explanation:

We know that the composition of Steel includes Carbon and Iron. So, if 2g of steel wool was added to the iron acetate, then the iron acetate is now being reduced. What will happen is that the solution will be triggered as it becomes denser and get highly concentrated. Hence, an increase in concentration leads to a decrease in reaction rates. Thus, a slow reaction will take place, and the reaction rate will decrease.

6 0
3 years ago
Balance this chemical equation
irina [24]

Answer:

3

Explanation:

On the left side we have 3 Calcium atoms and 6 fluorine atoms

that means there need to be the same number on the right side

in the CaF2 molecules we already have 2 fluorine atoms so by multiplying with 3 we get 3 Ca and 6F

3 0
3 years ago
Given the following: I) N20(g) 1/2 02(g) 2 NO(g) II) N2(g) 02(g) 2 NO(g) Ke= 4.1 x 10-31 Ke= 1.7 x 10-13 Find the value of the e
tresset_1 [31]

Answer:

Answer B) 4.2x10^17

Explanation:

To produce the reaction 3 using reaction 1 and 2 we need to invert the order of the first reaction the second in the same order, as it's shown:

2NO-------->N_2O+1/2O_2 : (reaction 1' :K'_1 =1/K_1=2.4x10^ 3^0)

N_2+O_2-------->2NO: (reaction 2 :K_2 =1.7x10^-^1^3)

____________________________

N_2+1/2O_2-------->N_2O: (reaction 3)

Due to the inversion of the first equation, the equilibrium constant of the new reaction is K1'=1/K1.=2.4x10^30

Finally, the new equilibrium constant K3 is the product of the previous constants:  

K3=K1'*K2=4.2x10^17

6 0
3 years ago
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