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3 years ago

In which point the electric intensity of a sphere is maximum

1 answer:

7 0

Here, as the charge is uniformly distributed in the sphere, we will consider s as an area of the sphere which is, s=4πr2 and r is radius of the gaussian surface shown in the figure above. From this, it can be seen that

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The volume of a gas decreases from 15.7 mºto 11.2 m3 while the pressure changes from 1.12 atm to 1.67 atm. If the

Svetlanka [38]

Answer:

Approximately $261\; \rm K$ , if this gas is an ideal gas, and that the quantity of this gas stayed constant during these changes.

Explanation:

Let $P_1$ and $P_2$ denote the pressure of this gas before and after the changes.

Let $V_1$ and $V_2$ denote the volume of this gas before and after the changes.

Let $T_1$ and $T_2$ denote the temperature (in degrees Kelvins) of this gas before and after the changes.

Let $n_1$ and $n_2$ denote the quantity (number of moles of gas particles) in this gas before and after the changes.

Assume that this gas is an ideal gas. By the ideal gas law, the ratios $\displaystyle \frac{P_1 \cdot V_1}{n_1 \cdot T_1}$ and $\displaystyle \frac{P_2 \cdot V_2}{n_2 \cdot T_2}$ should both be equal to the ideal gas constant, $R$ .

In other words:

$R = \displaystyle \frac{P_1 \cdot V_1}{n_1 \cdot T_1}$ .

$R =\displaystyle \frac{P_2 \cdot V_2}{n_2 \cdot T_2}$ .

Combine the two equations (equate the right-hand side) to obtain:

$\displaystyle \frac{P_1 \cdot V_1}{n_1 \cdot T_1} = \frac{P_2 \cdot V_2}{n_2 \cdot T_2}$ .

Rearrange this equation for an expression for $T_2$ , the temperature of this gas after the changes:

$\displaystyle T_2 = \frac{P_2}{P_1} \cdot \frac{V_2}{V_1} \cdot \frac{n_1}{n_2} \cdot T_1$ .

Assume that the container of this gas was sealed, such that the quantity of this gas stayed the same during these changes. Hence: $n_2 = n_1$ , $(n_2 / n_1) = 1$ .

$\begin{aligned} T_2 &= \frac{P_2}{P_1} \cdot \frac{V_2}{V_1} \cdot \frac{n_1}{n_2}\cdot T_1 \\[0.5em] &= \frac{1.67\; \rm atm}{1.12\; \rm atm} \times \frac{11.2\; \rm m^{3}}{15.7\; \rm m^{3}} \times 1 \times 245\; \rm K \\[0.5em] &\approx 261\; \rm K\end{aligned}$ .

4 0

3 years ago

¿Qué características debe tener el movimiento de una persona para que el valor del desplazamiento sea igual al de la distancia r

SIZIF [17.4K]

Explanation:

What characteristics must the movement of a person have so that the value of the displacement is equal to the distance traveled?

Displacement is equal to the shortest path covered by an object. It is given by the difference of final position and the initial position.

Distance is equal to the total path covered by an object during the journey.

When an object moves in a straight line path, in this case, the displacement is equal to the distance traveled.

3 0

3 years ago

You are on the roof of the physics building, 46.0 above the ground . Your physics professor, who is 1.80 tall, is walking alongs

Fudgin [204]

Answer:

3.6m

Explanation:

if you are at a building that is 46m above the ground, and the professor is 1.80m, the egg must fall:

46m - 1.80m = 44.2m

the egg must fall for 44.2m to land on the head of the professor.

Now, how many time this takes?

we have to use the following free fall equation:

$h=v_{0}t+\frac{1}{2}gt^2$

where $h$ is the height, $v_{0}$ is the initial velocity, in this case $v_{0}=0$ . $g$ is the acceleration of gravity: $g=9.81m/s$ and $t$ is time, thus: