Answer:
one or more cells
Explanation:
I need to have 20 characters to submit lol
Answer:
She must be launched with minimum speed of <u>57.67 m/s</u> to clear the 520 m gap.
Step-by-step explanation:
Given:
The angle of projection of the projectile is,
°
Range of the projectile is,
m.
Acceleration due to gravity, 
The minimum speed to cross the gap is the initial speed of the projectile and can be determined using the formula for range of projectile.
The range of projectile is given as:

Plug in all the given values and solve for minimum speed,
.

Therefore, she must be launched with minimum speed of 57.67 m/s to clear the 520 m gap.
4.096. You just have to multiply 1.6 three times. V=s^3
Answer:
68.5N
Explanation:
When the dolphin decelerates from 12m/s to 7.5 m/s within 2.3s. Then its acceleration is:

The dolphin has a mass of 35kg, according to the Newton's 2nd law, the force exerted on it must be:
