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2 years ago

Whiat is quantum numbers describes the size and energy of an orbital?

Physics

1 answer:

Levart [38]2 years ago

7 0

Answer:

The answer is the principal Quantum number (n)

Explanation:

The principal quantum number is one of the four quantum numbers associated with an atom.

It is denoted by a number n=1,2,3,4 etc

It tells both size (directly) and energy (indirectly) of an orbital.

When n=1 means it is the closest to the nucleus and is the smallest orbital and with increase in principal quantum number, it depicts that size of the orbital is increasing.

It tells the energy of the orbital as well as smaller number means less distance from nucleus and having less energy. Since electrons requires to absorb energy to jump into higher orbitals making n=2,3,4 etc. Thus electrons in the orbitals with higher n number indicates higher energy orbitals.

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Summarize renewable energy saves water and creates jobs

siniylev [52]

Answer: Solar Energy has been helping the supplying companies to be able to hire more people for jobs which helps 12 times more easier than the US, Things like solar, geothermal, and wind can help reduce the water resources which helps to save our water conservation rate which was getting increasingly High.

<em>I hope this explanation had helped you today!</em>

4 0

2 years ago

A solar cooker, really a concave mirror pointed at the Sun, focuses the Sun's rays 13.8 cm in front of the mirror. Part A What i

shepuryov [24]

From the concept of optics on a curvature of a spherical mirror, the proportion for which the focal length is equivalent to half the radius of curvature is fulfilled. Mathematically this is

$f = \frac{R}{2}$

Here,

f = Focal Length

R = Radius

Rearranging to find the radius we have,

$R = 2f$

Replacing with our values,

R = 2(13.8cm)

R = 27.6cm

Therefore the radius of the spherical surface from which the mirror was made is 27.6cm

6 0

2 years ago

Relate the structure of water to its ability to act as a solvent

pishuonlain [190]

Explanation:

Water (H2O) as a polar covalent molecule has its arrangement of oxygen and hydrogen atoms where one end (hydrogen) has a partially positive charge while the other side (oxygen) had a partially negative charge.

It is also capable of forming hydrogen bonds with polar molecules. Each water molecule can form two hydrogen bonds involving their hydrogen atoms and two further hydrogen bonds using the hydrogen atoms attached to neighboring water molecules.

5 0

2 years ago

Nathan is walking to the store and sees a snake slithering across the sidewalk. He jumps over it with an initial vertical veloci

Travka [436]

Answer:

$0.62\:\mathrm{s}$

Explanation:

Since the universal SI unit for velocity is meters/second, let's convert ft/s to m/s:

$10\:\mathrm{ft/s}=3.048\:\mathrm{m/s}$

We can use the following kinematics equation to solve this question:

$v_f=v_i+at$

What we know:

The initial velocity, $v_i$ , is $3.048\:\mathrm{m/s}$

(physics concept) The final velocity must be equal in magnitude but opposite in direction to the initial velocity ( $v_f=-3.048\:\mathrm{m/s}$ )
Acceleration, $a$ , is acceleration due to gravity at about $9.8\:\mathrm{m/s}$

Solving for $t$ :

$-3.048=3.048+(-9.8t),\\-6.096=-9.8t,\\t=\frac{-6.096}{-9.8}\approx \boxed{0.62\:\mathrm{s}}$

8 0

2 years ago

A thin rod (length = 1.09 m) is oriented vertically, with its bottom end attached to the floor by means of a frictionless hinge.

Murljashka [212]

Answer:

a) w = 4.24 rad / s , b) α = 8.99 rad / s²

Explanation:

a) For this exercise we use the conservation of kinetic energy,

Initial. Vertical bar

Emo = U = m g h

Final. Just before touching the floor

Emf = K = ½ I w2

As there is no friction the mechanical energy is conserved

Emo = emf

mgh = ½ m w²

The moment of inertial of a point mass is

I = m L²

m g h = ½ (m L²) w²

w = √ 2gh / L²

The initial height h when the bar is vertical is equal to the length of the bar

h = L

w = √ 2g / L

Let's calculate

w = RA (2 9.8 / 1.09)

w = 4.24 rad / s

b) Let's use Newton's equation for rotational motion

τ = I α

F L = (m L²) α

The force applied is the weight of the object, which is at a distance L from the point of gro

mg L = m L² α

α = g / L

α = 9.8 / 1.09

α = 8.99 rad / s²

5 0

3 years ago