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Nikitich [7]
3 years ago
9

Earthquakes and volcanic eruptions are examples of rapid events that are caused by the movement of Earth's _______. Mountain bui

lding is a much more slow process, which is caused by the movement of Earth's _______. A. Ocean tides; crustal plates B. Ocean tides; winds C. Crustal plates; crustal plates D. Crustal plates; ocean tides
Physics
2 answers:
andrew11 [14]3 years ago
5 0

The correct answer is - C. Crustal plates, crustal plates.

The movement of the crustal plates of the Earth is the reason why the geologic processes are occurring on our planet. With their movement, the crustal plates manage to create lot of pressure, open up gaps for the magma from the mantle, as well as make adjustments deeper into the ground.

Because of the adjustments deep into the ground, or rather the crust, lot of force is released, manifested as strong and very quick vibrations, better known as earthquakes.

The gaps that are opening between the plates let the magma reach the surface, thus enabling the volcanic activities on the planet.

The pressure from the plates' collision makes the land lift up slowly, and over time a mountain range starts to form because of the continuous lifting up of the area.

nydimaria [60]3 years ago
4 0

the answer is c just had this one

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4. List 3 detailed examples of Newton's 3rd Law.
slamgirl [31]

Answer:  If one billiard ball hits another, the second will move with the same force as the first.

A child wants to jump to climb a tree (reaction), he must push the ground to propel himself (action).

A man deflates a balloon; the force with which the air comes out causes the balloon to move from one side to the other.

Explanation:

7 0
3 years ago
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An electron is trapped in a one-dimensional infinite well of width 340 pm and is in its ground state. What are the (a) longest,
Nesterboy [21]

Answer:

(a) 1.2703×10⁻⁷ m

(b) 4.7636×10⁻⁸ m

(c) 2.5406×10⁻⁸ m

Explanation:

Given:

Width of the infinite well, L = 340 pm = 340×10⁻¹² m.

The formula for energy of the electron in nth state is:

E_n=\frac {n^2\times h^2}{8mL^2}

The expression for the difference in energy between the levels having quantum numbers n(initial) to n(final) is:

\Delta E_n=\frac {({n_f}^2-{n_i}^2)\times h^2}{8mL^2}

According to Planks theory:

E = hv

where, v is the frequency

Also,

Frequency×Wavelength = Speed of light

So,

E=\frac {hc}{\lambda}

\lambda=\frac {hc}{E}

Also,  using energy from above formula as:

\lambda=\frac {hc}{\frac {({n_f}^2-{n_i}^2)\times h^2}{8mL^2}}

\lambda=\frac {c\times {8mL^2}} {({n_f}^2-{n_i}^2)\times h}}

For longest wavelength ni = 1 and nf = 2

m= mass of the electron = 9.1 ×10⁻³¹kg

c = 3×10⁸m/s

h = 6.625×10⁻³⁴J.sec

\lambda_{Longest}=\frac {3\times 10^8\times {8\times 9.1\times 10^{-31}(340\times 10^{-12})^2}} {({2}^2-{1}^2)\times 6.625\times 10^{-34}}}

<u>Longest wavelength = 1.2703×10⁻⁷ m</u>

For second longest wavelength ni = 1 and nf = 3

\lambda_{Second\ Longest}=\frac {3\times 10^8\times {8\times 9.1\times 10^{-31}(340\times 10^{-12})^2}} {({3}^2-{1}^2)\times 6.625\times 10^{-34}}}

<u>Second longest wavelength = 4.7636×10⁻⁸ m</u>

For third longest wavelength ni = 1 and nf = 4

\lambda_{Third\ Longest}=\frac {3\times 10^8\times {8\times 9.1\times 10^{-31}(340\times 10^{-12})^2}} {({4}^2-{1}^2)\times 6.625\times 10^{-34}}}

<u>Third longest wavelength = 2.5406×10⁻⁸ m</u>

3 0
3 years ago
Two point charges of -7uC and 4uC are a distance of 20
aivan3 [116]

Answer:

Approximately 0.979 J.

Explanation:

Assume that the two charges are in vacuum. Apply the coulomb's law to find their initial and final electrical potential energy \mathrm{EPE}.

\displaystyle \mathrm{EPE} = \frac{k \cdot q_1 \cdot q_2}{r},

where

  • The coulomb's constant k = 8.99\times 10^{9}\; \rm N\cdot m^{2} \cdot C^{-2},
  • q_1 and q_2 are the sizes of the two charges, and
  • r is the separation of (the center of) the two charges.

Note that there's no negative sign before the fraction.

Make sure that all values are in SI units:

  • q_1 = -7\rm \;\mu C = -7\times 10^{-6}\; C;
  • q_2 = 4\rm \;\mu C = 4\times 10^{-6}\; C;
  • Initial separation: \rm 20\; cm = 0.20\; cm;
  • Final separation: \rm 90\; cm = 0.90\; cm.

Apply Coulomb's law:

Initial potential energy:

\begin{aligned} \frac{k \cdot q_1 \cdot q_2}{r} &= \frac{8.99\times 10^{9}\times (-7\times 10^{-6})\times 4\times 10^{-6}}{0.20}\\&= \rm -1.2586\; J\end{aligned}.

Final potential energy:

\begin{aligned} \frac{k \cdot q_1 \cdot q_2}{r} &= \frac{8.99\times 10^{9}\times (-7\times 10^{-6})\times 4\times 10^{-6}}{0.90}\\&= \rm -0.279689\; J\end{aligned}.

The final potential energy is less negative than the initial one. In other words, the two particles gain energy in this process. The energy difference (final minus initial) will be equal to the work required to move them at a constant speed.

\begin{aligned}\text{Work required} &= \text{Final EPE} - \text{Initial EPE}\\&= \rm  -0.279689\; J - (-1.2586\; J)\\&\approx 0.979\; J\end{aligned}.

8 0
3 years ago
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Romashka [77]
These waves most likely belong to the part<span> of the electromagnetic spectrum that contains radio waves, since radio waves have the lowest frequency of any of the other waves.</span>
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3 years ago
A center-seeking force related to acceleration is _______ force.
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5 0
4 years ago
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