Answer:3.54ohms
Explanation: connection in parallel
1/Rt= 1/R1+1/R2+1/R3
1/Rt= 1/16+1/13+1/7
1/Rt= 91+112+208/1456
1/Rt= 411/1456
411Rt= 1456
Rt= 1456/411
Rt= 3.54ohms
The amount of heat needed to raise the temperature of a substance by
is given by
where
m is the mass of the substance
Cs is its specific heat capacity
is the increase in temperature
For oxygen, the specific heat capacity is approximately
The variation of temperature for the sample in our problem is
while the mass is m=150 g, so the amount of heat needed is
Answer: option 1 : the electric potential will decrease with an increase in y
Explanation: The electric potential (V) is related to distance (in this case y) by the formulae below
V = kq/y
Where k = 1/4πε0
Where V = electric potential,
k = electric constant = 9×10^9,
y = distance of potential relative to a reference point, ε0 = permittivity of free space
q = magnitude of electronic charge = 1.609×10^-19 c
From the formulae, we can see that q and k are constants, only potential (V) and distance (y) are variables.
We have that
V = k/y
We see the potential(V) is inversely proportional to distance (y).
This implies that an increase in distance results to a decreasing potential and a decrease in distance results to an increase in potential.
This fact makes option 1 the correct answer
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Answer: 90 m/s
Explanation:
Given
mass of racecar 
velocity of racecar 
mass of still honeybadger 
after collision race car is traveling at a speed of 
conserving linear momentum
![Mu+m\times0=Mv_1+ mv_2\quad[v_2=\text{velocity of honeybadger after colllision}]](https://tex.z-dn.net/?f=Mu%2Bm%5Ctimes0%3DMv_1%2B%20mv_2%5Cquad%5Bv_2%3D%5Ctext%7Bvelocity%20of%20honeybadger%20after%20colllision%7D%5D)
