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Aleonysh [2.5K]
3 years ago
5

65mi/hr South is an example of​

Physics
1 answer:
Shtirlitz [24]3 years ago
8 0

Answer:

It's an example of velocity.

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I’m struggling... please help
Phantasy [73]

Answer:

M. A change that causes the gene to increase the amount of lactase ir produces will increase a person's ability to break down lactose

Explanation:

Lactose is a sugar found in dairy products. Humans require an enzyme, called lactase, to break down the sugar in the body. This enzyme is produced by the lactase gene.

Some people have some variation in their gene that means they do not produce very much lactase. This means they do not produce sufficient amount of the enzyme to break down the sugar lactose found in milk. This causes them to feel ill and get abdominal pain when they eat dairy, because their body can't break down the sugar.

Therefore, a change in the gene that causes it to produce more lactase will make people more able to consume lactase. A change that decreases the amount of lactase enzyme will have the opposite effect.

The source of protein and minerals found in dairy are not processed by lactase, so R is not correct.

4 0
4 years ago
Find the acceleration for a force of 2 N acting on 2 kg.
igomit [66]

Answer:

The acceleration of a 2 kg box acted on by a net force of 2 N is solved by using Newton’s second law of motion in the form acceleration = F_net / mass. Since the mass of the box is 2 kg and the net force is 2 N, the acceleration of the 2 kg box is 1 m/s^2.

4 0
3 years ago
A car and a train move together along straight, parallel paths with the same constant cruising speed v(initial). At t=0 the car
kogti [31]

Answer:

t_1 = \frac{v_i}{a_i}

t_2 = \frac{v_i}{a_i}

Δd = v_it_1 = v_i^2/a_i

Explanation:

As v(t) = v_i + at, when the car is making full stop, v(t_1) = 0 . a = -a_i . Therefore,

0 = v_i - a_it_1\\v_i = a_it_1\\t_1 = \frac{v_i}{a_i}

Apply the same formula above, with v(t_2) = v_i and a = a_i, and the car is starting from 0 speed,  we have

v_i = 0 + a_it_2\\t_2 = \frac{v_i}{a_i}

As s(t) = vt + \frac{at^2}{2}. After t = t_1 + t_2, the car would have traveled a distance of

s(t) = s(t_1) + s(t_2)\\s(t_1) = (v_it_1 - \frac{a_it_1^2}{2})\\ s(t_2) = \frac{a_it_2^2}{2}

Hence s(t) = (v_it_1 - \frac{a_it_1^2}{2}) + \frac{a_it_2^2}{2}

As t_1 = t_2 we can simplify s(t) = v_it_1

After t time, the train would have traveled a distance of s(t) = v_i(t_1 + t_2) = 2v_it_1

Therefore, Δd would be 2v_it_1 - v_it_1 = v_it_1 = v_i^2/a_i

8 0
3 years ago
If you hold one end of a nail against a piece of ice, the end in your hand soon becomes cold. Does cold flow
kvv77 [185]
Not ice to hand, but ice to nail to hand. The longer you have the nail on the ice the colder it becomes. Therefore resulting in your hand becoming colder.
7 0
3 years ago
A brass rod with a mass of 0.300 kg slides on parallel horizontal iron rails, 0.440 m apart, and carries a current of 15.0 A. Th
Digiron [165]

Answer:

The magnitude of the magnetic field is  B  =  0.0890 \ T

Explanation:

From the question we are told that

   The mass of the rod is  m =0.300 \ kg

    The distance of separation is  d = 0.440 \ m

     The current is  I  = 15.0 \ A

     The coefficient of friction is   \mu  =  0.300

     

Generally for the rod the rod to continue moving at a constant speed

   The frictional force must equal to the magnetic field force so

    F_m =  F_f

Where  F_m  =  B* I * d

and     F_f  =  \mu * m * g

   B*I *d =  \mu * m * g

=>    B  =  \frac{\mu * m * g }{I  * d }

substituting values

       B  =  \frac{0.2  * 0.300 * 9.8 }{ 15   * 0.440 }

       B  =  0.0890 \ T

8 0
3 years ago
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