Answer: Sanjay can burn 100 more calories every 30 minutes if he chooses to lift weights instead of watching tv
Explanation: 133-33= 100 calories (says in article and i just answered it)
Explanation:
Equation for energy balance will be as follows.
Hence, 
Therefore, we will calculate the final temperature as follows.
= 868.03 R
Now, we will calculate the mass as follows.
m = 
= 
= 1.031 lbm
Hence,
Putting the values into the above equation as follows.
= 655.2 Btu
Thus, we can conclude that work done by paddle wheel is 655.2 Btu.
Nuclear fission formula by the looks of it. Possibly how Professor Lisa Meitner realised that she had split the atomic nucleus. The Xenon and the Strontium (Xe and Sr) would presumably show up in a radio chemical assaying test at her university.
A few years later, Professor J Robert Oppenheimer watched a nuclear test somewhere near Los Alamos, US and lamented "I am become death, the destroyer of worlds". Shortly thereafter, Hiroshima and Nagasaki were razed to the ground and annihilated by nuclear bombs. Professor Meitner, probably inadvertently, had got the keys to the doors to "nuclear hell", and JRO ended up turning them. Something like that maybe, and a very harrowing and tumultuous period in human history.
Note in the fission equation, that out come two neutrons. They go off and produce a similar fission in another U235 nucleus into a chain reaction which, i not moderated by, say, Boron, can end up as a "mushroom cloud".
Answer:
K_a = 8,111 J
Explanation:
This is a collision exercise, let's define the system as formed by the two particles A and B, in this way the forces during the collision are internal and the moment is conserved
initial instant. Just before dropping the particles
p₀ = 0
final moment
p_f = m_a v_a + m_b v_b
p₀ = p_f
0 = m_a v_a + m_b v_b
tells us that
m_a = 8 m_b
0 = 8 m_b v_a + m_b v_b
v_b = - 8 v_a (1)
indicate that the transfer is complete, therefore the kinematic energy is conserved
starting point
Em₀ = K₀ = 73 J
final point. After separating the body
Em_f = K_f = ½ m_a v_a² + ½ m_b v_b²
K₀ = K_f
73 = ½ m_a (v_a² + v_b² / 8)
we substitute equation 1
73 = ½ m_a (v_a² + 8² v_a² / 8)
73 = ½ m_a (9 v_a²)
73/9 = ½ m_a (v_a²) = K_a
K_a = 8,111 J
The Acceleration of the system is 6.41 m/s².
Given,
α= 15°, m₁ = 7kg
β= 65°, m₂ = 11 kg
Let, a be the acceleration and T is the tensions at the end it's the cord.
Let, the mass m₂ be coming down along the inclined plane along the inclined surface towards downward m₂g sin β and the tension in the upward direction,
Resultant force, m₂a=m₂g sin β -T
11a=((11) ×g sin 65°) -T ...(i)
Now, considering the motion of m₁ which moves downwards, the forces are m₁g sinα, and T both are acting downwards.
Resultant force m₁a = m₁g sin α+T
7a =7g sin 15°+T ...(ii)
Solving both the equations by adding them,
18a=11gsin 65°+7g sin 15°-T+T
18a=11gsin 65°+7g sin 15°=115.45
a=115.45/18=6.41 m/s²
Hence, the Acceleration of the system is 6.41 m/s².
Learn more about the acceleration here:
brainly.com/question/22048837
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