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Vaselesa [24]
3 years ago
14

Problems 307 How many milliliters of a 2.5 M NaCl solution would be needed to prepare each solution? a. 1.5L of a 0.75m solution

​
Chemistry
1 answer:
mafiozo [28]3 years ago
5 0

Answer:

450 mL

Explanation:

First we <u>calculate how many NaCl moles would there be in 1.5 L of a 0.75 M solution</u>, using the <em>definition of molarity</em>:

  • Molarity = moles / Liters
  • Moles = Molarity * Liters
  • Moles = 1.5 L * 0.75 M =1.125 mol

Once again using the <em>definition of molarity</em>, we now <u>calculate how many liters of a 2.5 M solution would have 1.125 moles</u>:

  • Liters = 1.125 mol / 2.5 M = 0.45 L

Finally we <u>convert 0.45 liters to mL</u>:

  • 0.45 L * 1000 = 450 mL
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Pls help
Irina-Kira [14]

Answer:

CrO₂ --------------------> Cr⁴⁺ and O²⁻

VCO₃ -------------------> V²⁺ and CO₃²⁻

Cr₂(SO₄)₃ -------------> Cr³⁺ and SO₄²⁻

(NH₄)₂S ----------------> NH₄⁺ and S²⁻

Explanation:

Within ionic compounds, the cation is listed first, followed by the anion. Some of the ions are polyatomic, meaning they are covalently bonded to other elements. Polyatomic ions always have a specific charge.

All of these ionic compounds have an overall charge of 0. As such, the charges of the cations and anions must balance out. In order to do so, there are some compounds which have more than one atom of each ion.

2.) CrO₂

------> Oxygen (O) always forms the anion, O²⁻.

------> Therefore, if there are 2 oxygen anions, the chromium (Cr) must have the cationic form of Cr⁴⁺.

------> +4 + (-2) + (-2) = 0

3.) VCO₃

------> Carbonate (CO₃), a polyatomic ion, always has the state CO₃²⁻.

------> If there is only one atom of each ion, the charges must perfectly balance, making vanadium (V) be the cation V²⁺.

------> +2 + (-2) = 0

4.) Cr₂(SO₄)₃

------> Sulfate (SO₄), a polyatomic ion, always has the state SO₄²⁻.

-------> The only way the charges could balance out is if the chromium (Cr) is in the cationic form Cr³⁺.

------> +3 + 3 + (-2) + (-2) + (-2) = 0

5.) (NH₄)₂S

------> Ammonium (NH₄), a polyatomic ion, always has the state NH₄⁺.

------> Sulfur (S) always forms the anion S²⁻.

------> +1 + 1 + (-2) = 0

3 0
2 years ago
Which of the following statements are true? (There are 2)
Shalnov [3]

Answer:

A and B

Explanation:

the other two make no sense at all

4 0
2 years ago
Read 2 more answers
Consider dissolving sugar in water and magnesium sulfate in water. is any new substance being produced? what happens after sodiu
Olenka [21]

Answer:

Here's what I get  

Explanation:

1. Sugar

(a) Dissolving in water

The white solid dissolves in water to give a colourless solution. There is no evidence that a new substance is being produced.

(b) Addition of sodium hydroxide

Adding the colourless solution of sodium hydroxide to the colourless sugar solution gives a colourless solution. There is no evidence that a new substance is being produced.

2. Magnesium sulfate

(a) Dissolving in water

The colourless crystals dissolve in water to give a colourless solution. There is no evidence that a new substance is being produced.

(b) Addition of sodium hydroxide

Adding the colourless solution of sodium hydroxide to the colourless solution of magnesium sulfate gives a white precipitate (see image). This is evidence that a new substance is being produced.

8 0
3 years ago
Potassium hydroxide is classified as an arrhenius base because koh contains
mixas84 [53]

Answer: hydroxide ions

Explanation:

According to the Arrhenius concept, an acid is a substance that ionizes in the water to give hydronium ion or hydrogen ion  and a bases is a substance that ionizes in the water to give hydroxide ion .

According to the Bronsted Lowry conjugate acid-base theory, an acid is defined as a substance which donates protons and a base is defined as a substance which accepts protons.

According to the Lewis concept, an acid is defined as a substance that accepts electron pairs and base is defined as a substance which donates electron pairs.

As KOH can give hydroxide ions on dissociation , it is considered as arrhenius base.

KOH\rightarrow K^++OH^-

8 0
3 years ago
What is the name of this hydrocarbon? 2–methylpentyne 2–dimethylpentene 2,3–dimethylpentane 3,2–dimethylpentane
Phantasy [73]
<span>on plato it's 2,3–dimethylpentane

</span>
6 0
3 years ago
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