Answer:
C) 64lb
Explanation:
use the linearity method to find the weight of nadir on another planet, it is applied as follows.
Nadir Weight in earth ⇒ Nadir weight in another planet
Vince Weigh in eart ⇒ X
our goal is to find the weight of vince in another planet (X), for this we multiply the diagonal that continents the data and divide among the remaining
140pounds ⇒ 56lb
160pounds ⇒ X
X=
Vince weigh on the other planet is C) 64lb
Answer:443.1 s
Explanation:
Given
Engine of a locomotive exerts a force of 
Mass of train
Final speed (v)
F=ma
so 

and acceleration is



1 ft =12 in
4 in = 0.333 ft
volume = (п/4)*(0.333)² = 0.087 ft²
vol. flow = spead *volume
=3 ft/s * 0.087 ft²
vol flow = 0.261 ft³/s
Answer:
k = 17043.5 N/m = 17.04 KN/m
Explanation:
First we need to find the force applied by safe pn the spring:
F = Weight of Safe
F = mg
where,
F = Force Applied by the safe on the spring = ?
m = mass of safe = 800 kg
g = 9.8 m/s²
Therefore,
F = (800 kg)(9.8 m/s²)
F = 7840 N
Now, using Hooke's Law:
F = kΔx
where,
K = Spring Constant = ?
Δx = compression = 46 cm = 0.46 m
Therefore,
7840 N = k (0.46 m)
k = 7840 N/0.46 m
<u>k = 17043.5 N/m = 17.04 KN/m</u>
What happens when you pour water in a glass? It takes the shape of the glass. This means that water can't have a fixed shape or volume