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boyakko [2]
3 years ago
5

What is the resultant of a pair of forces, 100N, upward and 75N, downward?

Physics
1 answer:
soldi70 [24.7K]3 years ago
3 0

Answer:

25N

Explanation:

100 - 75 = 25

That should be right if im not dumb...

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Describe your acceleration as you skate down your neighborhood sidewalk.
Paraphin [41]

Answer: when you increase or decrease your speed.

Explanation:

Moving a skate at rest, you need to apply force in order to cause acceleration.

F = ma Where

F = force applied

m = mass of the skate

a = acceleration

The initial velocity u will be equal to zero and the skate will acceleration to a certain velocity.

as you skate down your neighborhood sidewalk, you will accelerate when you increase your speed. Because

Acceleration is the rate of change of velocity. That is,

Acceleration = change in velocity/ time.

And also, you will decelerate when you reduce the speed or velocity down your neighborhood sidewalk.

6 0
3 years ago
Two strong magnets were brought close to each other. They were repelling each other. Explain what must have happened.​
r-ruslan [8.4K]

When two magnets are brought together, the opposite poles will attract one another, but the like poles will repel one another. This is similar to electric charges. Like charges repel, and unlike charges attract.

pls. mark brainliest am. dyning for it

8 0
2 years ago
Read 2 more answers
List three measurements with different units this are equal to 5 meters
olganol [36]
5kg
50cm
500in
Hope this helped good luck to you
6 0
3 years ago
A car in an amusement park ride rolls without friction around a track (Fig. P7.42). The hB car starts from rest at point A at a
MrRissso [65]

Answer:

h>\dfrac{5}{2}R

Explanation:

Given that

Height = h

Radius = R

From energy conservation

KE_A+U_A=KE_B+U_B

At point B

The minimum speed to complete the   the circle

V_B=\sqrt{gR}\ m/s

So the kinetic energy at point B

KE_B=\dfrac{1}{2}mV^2

KE_B=\dfrac{1}{2}mgR

KE_A+U_A=KE_B+U_B

0+mgh=\dfrac{1}{2}mgR+2mgR

Without falling off at the top (point B)

0+mgh>\dfrac{1}{2}mgR+2mgR

mg(h-2R)>\dfrac{1}{2}mgR

g(h-2R)>\dfrac{1}{2}gR

h>\dfrac{5}{2}R

6 0
3 years ago
provides one model for solving this problem. The maximum strength of the earth's magnetic field is about 6.9 x 10-5 T near the s
jeka57 [31]

Answer:

The minimum no. of turns is 3.126 \times 10^{5}

Explanation:

Given:

Magnetic field B = 6.9 \times 10^{-5} T

Frequency f = 84.5 Hz

Area of turn A = 0.021 m^{2}

Voltage V_{rms}  = 170 V

From the formula of induced emf,

V = NBA \omega

Where \omega = 2\pi f and V = \sqrt{2} V_{rms}

So number of turn is,

N = \frac{\sqrt{2} V_{rms} }{AB2\pi f }

N = \frac{\sqrt{2} \times 170 }{0.021 \times 6.9 \times 10^{-5} \times 6.28 \times 84.5 }

N = 3.126 \times 10^{5}

Therefore, the minimum no. of turns is 3.126 \times 10^{5}

4 0
3 years ago
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