How many protons does this atom have?

A 4kg block moving right at 6 m/s collides elastically with a 2kg block moving right at 3 m/s find their final velocity

nignag [31]

The final velocity of block 1 is 2.2m/s and the final velocity of block 2 is 3.4m/s.

<h3>What do you mean by elastically?</h3>

Although the terms scalability and elasticity are occasionally used interchangeably, scalability is more commonly used to describe a system's ability to successfully handle an increasing workload, while elasticity implies that the system is also capable of rapidly expanding or decreasing capacity and services. The capacity of an IT environment to grow and shrink in response to business requirements is one of its characteristics. Physics defines resilience as a material's ability to absorb energy and react elastically in order to maintain its integrity and avoid deforming as a result of the pressures it is subjected to.

To learn more about elastically, Visit:

brainly.com/question/24291236

#SPJ4

6 0

2 years ago

The frequency and wavelength of EM waves can vary over a wide range of values. Scientists refer to the full range of frequencies

mestny [16]

Complete question is;

The frequency and wavelength of EM waves can vary over a wide range of values. Scientists refer to the full range of frequencies that EM radiation can have as the electromagnetic spectrum. Electromagnetic waves are used extensively in modern wireless technology. Many devices are built to emit and/or receive EM waves at a very specific frequency, or within a narrow band of frequencies. Here are some examples followed by their frequencies of operation:

garage door openers: 40.0 MHz

standard cordless phones: 40.0 to 50.0 MHz

baby monitors: 49.0 MHz

FM radio stations: 88.0 to 108 MHz

cell phones: 800 to 900 MHz

Global Positioning System: 1227 to 1575 MHz

microwave ovens: 2450 MHz

wireless internet technology: 2.4 to 2.6 GHz

Which of the following statements correctly describe the various applications listed above? Check all that apply.

a.) All these technologies use radio waves, including low-frequency microwaves.

b.) All these technologies use radio waves, including high-frequency microwaves.

c.) All these technologies use a combination of infrared waves and high-frequency microwaves.

d.) Microwave ovens emit in the same frequency band as some wireless Internet devices.

e.) The radiation emitted by wireless Internet devices has the shortest wavelength of all the technologies listed above.

f.) All these technologies emit waves with a wavelength in the range of 0.10 to 10.0 m.

g.) All the technologies emit waves with a wavelength in the range of 0.01 to 10.0 km.

Answer:

B, D, E, F are the correct statements.

Explanation:

Looking at the options;

A) This is true because radio waves are electromagnetic radiation being used today in television, mobile phones, radios and other areas of communication technologies. And the examples given to us fall in the category of technologies that use radio waves.

B) microwaves usually have long wavelengths and low frequencies. However, sometimes they could have high frequencies usually more than radio waves. Thus, this option is correct.

C) This option is wrong because it's not all the listed technologies that use combination of infrared waves and high-frequency microwaves.

D) we are given the frequency of microwave ovens as 2450 MHz.

Converting to GHz gives; 2.45 GHz.

We are told that wireless internet technology has frequency between 2.4 to 2.6 GHz. Thus, microwave frequency falls in the same range as wireless internet technology and thus the statement is true.

E) we know that wavelength is inversely proportional to frequency. This means that the higher the frequency, the shorter the wavelength.

In the frequencies given to us, wireless internet technology have the highest frequency which means they have the shortest wavelength. The statement is true.

F) from the frequencies given to us, the smallest is garage door openers = 40.0 MHz = 40 × 10^(6) Hz while the biggest is 2.6 GHz = 2.6 × 10^(9) Hz

Formula for wavelength is;

Wavelength = speed of light/frequency

Speed of light = 3 × 10^(8) m/s

Thus;

Wavelength = (3 × 10^(8))/(40 × 10^(6))

Or wavelength = (3 × 10^(8))/(2.6 × 10^(9))

So,wavelength = 7.5 m or 0.12 m

This falls into the given range of 0.10 to 10.0 m.

Thus, the statement is true.

8 0

3 years ago

A beam of white light passes through a uniform thickness of air. If the intensity of the scattered light in the middle of the gr

k0ka [10]

This question is incomplete, the complete question is;

A beam of white light passes through a uniform thickness of air. If the intensity of the scattered light in the middle of the green part of the visible spectrum (λ=520nm) is I, find the intensity (in terms of I) of scattered light

a) In the middle of the red part of the spectrum (λ= 665 nm)

b) In the middle of the violet part of the spectrum (λ = 420 nm)

Answer:

a) the intensity of scattered light ( in terms of $I$ ) In the middle of the red part of the spectrum is 0.3739 $I$

b) the intensity of scattered light ( in terms of $I$ ) In the middle of the violet part of the spectrum is 2.3497 $I$

Explanation:

Given the data in the question,

the visible spectrum (λ=520nm) = $I$

we know that; intensity of scattered light is proportional to 1 / λ⁴

$I$ ∝ ( 1 / λ⁴ )

so

a)

$I_R$ / $I$ = ( λ / λ $_R$ )⁴

As the middle of the green part of the visible spectrum λ is 520nm and middle of the red part of the spectrum λ $_R$ is 665 nm

we substitute

$I_R$ / $I$ = ( 520 / 665 )⁴

$I_R$ / $I$ = ( 0.781954887 )⁴

$I_R$ / $I$ = 0.3739

$I_R$ = 0.3739 $I$ { in terms of $I$ }

Therefore, the intensity of scattered light ( in terms of $I$ ) In the middle of the red part of the spectrum is 0.3739 $I$

b)

$I_V$ / $I$ = ( λ / λ $_V$ )⁴

As the middle of the green part of the visible spectrum λ is 520nm and middle of the red part of the spectrum λ $_R$ is 420 nm

we substitute

$I_V$ / $I$ = ( 520 / 420 )⁴

$I_V$ / $I$ = ( 1.238095 )⁴

$I_V$ / $I$ = 2.3497

$I_V$ = 2.3497 $I$ { in terms of $I$ }

Therefore, the intensity of scattered light ( in terms of $I$ ) In the middle of the violet part of the spectrum is 2.3497 $I$

5 0

3 years ago

Read 2 more answers

A car with mass 1500 kg moves with constant velocity of 36 m/s. The driver sees a group of cows in front and he immediately step

Crazy boy [7]

From laws of motion:

$S = ( \frac{v + u}{2} ) \times t$
Where S is the distance/displacement (as you would call it) which is unknown
v = final velocity which is 0m/s (this is because the car stops)
u = initial velocity which is 36m/s (from the data given)
t = time taken for the distance to be covered and it is 6s

Substitute the values, hence:
$S = ( \frac{0 + 36}{2} ) \times 6$
$S = (18) \times 6 \\ \\ S = 108m$

But this is merely the distance he travelled in the 6 seconds he was trying to stop the car.

Therefore, the distance between the car and the cows = 160-108
Distance = 52m

6 0

4 years ago

When a honeybee flies through the air, it develops a charge of +20 pC . Part A How many electrons did it lose in the process of

Yuri [45]

Answer:

1.3 × 10⁸ e⁻

Explanation:

When a honeybee flies through the air, it develops a charge of +20 pC = + 20 × 10⁻¹² C. This is a consequence of losing electrons (negative charges). The charge of 1 mole of electrons is 96468 C (Faraday's constant). The moles of electrons representing 20 pC are:

20 × 10⁻¹² C × (1 mol e⁻/ 96468 C) = 2.1 × 10⁻¹⁶ mol e⁻

1 mole of electrons has 6.02 × 10²³ electrons (Avogadro's number). The electrons is 2.1 × 10⁻¹⁶ moles of electrons are:

2.1 × 10⁻¹⁶ mol e⁻ × (6.02 × 10²³ e⁻/ 1 mol e⁻) = 1.3 × 10⁸ e⁻

7 0

4 years ago