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iragen [17]
3 years ago
8

A 30-kg child starts at the center of a playground merry-go-round that has a radius of 2.1 m and rotational inertia of 500 kg⋅m2

and walks out to the edge. The merry-go-round has a rotational speed of 0.20 s−1 when she is at the center?
Physics
1 answer:
Sever21 [200]3 years ago
8 0

Answer:

\omega = 0.16 s^{-1}

Explanation:

As we know that there is no torque on the system of merry go round

so the angular momentum will remain conserved

so here we have

I_1\omega_0 = (I_1 + I_2)\omega

so we will have

I_1 = 500 kg m^2

I_2 = 30(2.1^2)

I_2 = 132.3 kg m^2

\omega_0 = 0.20 s^{-1}

now from above formula

500(0.20) = (500 + 132.3)\omega

\omega = 0.16 s^{-1}

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Plzzz answer this question correctly
tekilochka [14]

Answer:

changing the direction in which a force is exerted

8 0
3 years ago
1pt A cannon fires a 5-kg ball horizontally from a
Klio2033 [76]

Answer: Both cannonballs will hit the ground at the same time.

Explanation:

Suppose that a given object is on the air. The only force acting on the object (if we ignore air friction and such) will be the gravitational force.

then the acceleration equation is only on the vertical axis, and can be written as:

a(t) = -(9.8 m/s^2)

Now, to get the vertical velocity equation, we need to integrate over time.

v(t) = -(9.8 m/s^2)*t + v0

Where v0 is the initial velocity of the object in the vertical axis.

if the object is dropped (or it only has initial velocity on the horizontal axis) then v0 = 0m/s

and:

v(t) = -(9.8 m/s^2)*t

Now, if two objects are initially at the same height (both cannonballs start 1 m above the ground)

And both objects have the same vertical velocity, we can conclude that both objects will hit the ground at the same time.

You can notice that the fact that one ball is fired horizontally and the other is only dropped does not affect this, because we only analyze the vertical problem, not the horizontal one. (This is something useful to remember, we can separate the vertical and horizontal movement in these type of problems)

7 0
3 years ago
Why does a dropped object only fall 5 meters down after 1 second of freefall, yet achieve a speed of 10m/s?
andrew11 [14]

A dropped object only fall 5 meters down after 1 second of freefall, yet achieve a speed of 10m/s due to acceleration due to gravity.

s = vt - 1 / 2 at²

s = Displacement

v = Final velocity

t = Time

a = Acceleration

s = 5 m

t = 1 s

a = 10 m / s²

5 = ( v * 1 ) - ( 1 / 2 * 10 * 1 * 1 )

5 = v - 5

v = 10 m / s

The equation used to solve the given problem is an equation of motion. In a free fall motion, usually air resistance is not considered for easier calculation. If air resistance is considered acceleration cannot be constant throughout the entire motion.

Therefore, a dropped object only fall 5 meters down after 1 second of freefall, yet achieve a speed of 10m/s due to acceleration due to gravity.

To know more about equation of motion

brainly.com/question/5955789

#SPJ1

4 0
1 year ago
Please help me
g100num [7]

Answer:

0.3956

Explanation:

Newton's 2nd law of motion says that Force = Mass*Acceleration (f=ma) so to find the force used on the football you multiply it's mass by its acceleration.

0.43*0.92 = 0.3956.

0.4 if you round

5 0
3 years ago
The velocity of an object is positive and steadily increasing. Which of the following graphs represents how the acceleration of
stiv31 [10]
If an object's velocity is steadily increasing it means that the acceleration is constant at a certain value.

Choice A shows an acceleration of zero which would only be true if the object was not moving or if its velocity was not changing.

Choice B gives us a graph showing acceleration increasing over time and is therefore incorrect.

Choice C is correct because the acceleration is constant. Steadily increasing tells us that the acceleration is fixed at a certain value.

Choice D is incorrect an represents a constant negative acceleration. This would be the case if the object was steadily decreasing in velocity.




4 0
3 years ago
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