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Inessa05 [86]
3 years ago
11

During a thunderstorm, you should crouch under a tree for shelter. a. True b. False

Physics
1 answer:
nika2105 [10]3 years ago
5 0
The answer is b. False
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John wants a new video tape and a new shirt, but he only has $12.00. He buys the video tape and gets $0.52 change. What was his
mestny [16]

Answer:

You have the answer in your comments. I will be copying it so your question doesn't get deleted.

The answers is $0.58

$11.48

the video tape

the new shirt

7 0
3 years ago
If a car accelerates from rest at a constant of rate of 5.5m/s^2 north, how long will it take for the car to reach a velocity of
Bingel [31]

Answer:

Explanation:

vo= 0

a=5.5m/s^2

v= 28 m/s

t=?

v=vo+at

at=v-vo

t=(v-vo)/a

t=28/5.5

t=5.09 seconds

4 0
3 years ago
A horizontal 52-n force is needed to slide a 50-kg box across a flat surface at a constant velocity of 3.5 m/s. What is the coef
3241004551 [841]

Answer: 0.61

Explanation:

This is calculation based on friction.

Since the box rests on a flat surface, the force that exists between them is known as frictional force.

Since the friction is dynamic (velocity is not zero)

The frictional force = kinetic energy gained by the body.

Ff = 1/2mv^2

coefficient of kinetic friction × normal reaction = 1/2mv^2

Since normal reaction is equal to the weight(force acting along the vertical component)

Normal reaction= mg = 50 × 10 = 500N. Therefore,

coefficient of kinetic friction × 500 = 1/2×50×3.5^2

coefficient of kinetic friction = 50×3.5^2/1000

coefficient of kinetic friction= 0.61

6 0
3 years ago
Select the correct answer. A ball is thrown straight down from the top of a building at a velocity of 16 ft/s. The building is 4
BartSMP [9]

Answer:

The ball takes 5s to reach the ground

Explanation:

in order to solve this problem we use the kinematics equation with gravity as acceleration:

h=v_0t+1/2*gt^2

we replace the values

0=1/2*32t^2+16t-480

We solve this quadratic equation:

t=5s

t=-6s   (this solution has not physical sense)

8 0
3 years ago
Calculate the force it would take to accelerate a 650-kg vehicle at a rate of 3 m/s^2
aleksklad [387]

Explanation:

Newton's second law:

F = ma

F = (650 kg) (3 m/s²)

F = 1950 N

3 0
4 years ago
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