3 years ago

What must be applied to move a load?

2 answers:

5 0

A larger force than the object in question would be required to move an object. If the force is smaller, the object will not move and the force will be repelled.

Misha Larkins [42]3 years ago

3 0

An applied force must be applied to move a load. This applied force must be large enough to overcome any opposing forces in order to move the load.

You might be interested in

Which of these does NOT use a reed?<br> O Flute<br> Clarinet<br> Oboe<br> Bassoon

Lemur [1.5K]

Flute~~~~~~~~~~~~~~~~~~~

5 0

2 years ago

Read 2 more answers

Lexington walked to her friends house.lexie walked 2miles west then 5 miles south then 3 miles east then 4 miles north then 2 mi

vampirchik [111]

The answer is 17 for the miles

4 0

3 years ago

What is the process called when the moon begins to fade from a full moon to the new moon?

satela [25.4K]

Answer: Waning

Explanation: Not much explanation for this

8 0

3 years ago

A spring with spring constant 11.5 N/m hangs from the ceiling. A 490 g ball is attached to the spring and allowed to come to res

Natalija [7]

Answer:

The time constant is $\tau = 17.5 \ s$

Explanation:

From the question we are told that

The spring constant is $k = 11.5 \ N/m$

The mass of the ball is $m_b = 490 \ g = 0.49 \ kg$

The amplitude of the oscillation t the beginning is $x = 6.70 cm = 0.067 \ m$

The amplitude after time t is $x_t = 2.20 cm = 0.022 \ m$

The number of oscillation is $N = 30$

Generally the time taken to attain the second amplitude is mathematically represented as

$t = N * T$ Here T is the period of oscillation

$t = N * 2\pi \sqrt{\frac{m}{k} }$

=> $t = 30 * 2 * 3.142 * \sqrt{\frac{ 0.490}{11.5} }$

=> $t = 38.88 \ s$

Generally the amplitude at time t is mathematically represented as

$x(t) = x e^{-\frac{at}{2m} }$

Here a is the damping constant so

at $t = 38.88 \ s$ , $x_t = 2.20 cm = 0.022 \ m$

$0.022 = 0.067 e^{-\frac{a * 38.88}{2 * 0.490} }$

=> $0.3284 = e^{-\frac{a * 38.88}{2 * 0.490} }$

taking natural log of both sides

=> $ln(0.3284 ) = -\frac{a * 38.88}{2 * 0.490} }$

=> $a = 0.028$

Generally the time constant is mathematically represented as

$\tau = \frac{m}{a}$

=> $\tau = \frac{0.490}{ 0.028}$

=> $\tau = 17.5 \ s$

4 0

3 years ago

The moon and other satellites rotate around the earth. Identify the force that keeps these satellites in orbit. A) gravity B) fr

RoseWind [281]

The force is gravity

4 0

3 years ago

Read 2 more answers