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4 years ago

What must be applied to move a load?

2 answers:

5 0

A larger force than the object in question would be required to move an object. If the force is smaller, the object will not move and the force will be repelled.

Misha Larkins [42]4 years ago

3 0

An applied force must be applied to move a load. This applied force must be large enough to overcome any opposing forces in order to move the load.

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Consider a bicycle wheel to be a ring of radius 30 cm and mass 1.5 kg. Neglect the mass of the axle and sprocket. If a force of

Charra [1.4K]

To solve the problem it is necessary to apply the Torque equations and their respective definitions.

The Torque is defined as,

$\tau = I \alpha$

Where,

I=Inertial Moment

$\alpha =$ Angular acceleration

Also Torque with linear equation is defined as,

$\tau = F*d$

Where,

F = Force

d= distance

Our dates are given as,

R = 30 cm = 0.3m

m = 1.5 kg

F = 20 N

r = 4.0 cm = 0.04 m

t = 4.0s

Therefore matching two equation we have that,

$d*F = I\alpha$

For a wheel the moment inertia is defined as,

I= mR2, replacing we have

$d*F= \frac{mR^2a}{R}$

$d*F= mRa$

$a = \frac{rF}{ mR}$

$a = \frac{0.04*20}{1.5*0.3}$

$a=1.77 m/s^2$

Then the velocity of the wheel is

$V = a *t \\V=1.77*4 \\V=7.11 m/s$

Therefore the correct answer is D.

4 0

3 years ago

In the 1887 experiment by Michelson and Morley, the length of each interferometer arm was 11m. The experimental limit on the mea

Vikentia [17]

For the answer to the question above,
we can get the number of fringes by dividing (delta t) by the period of the light (Which is λ/c).

fringe = (delta t) / (λ/c)

We can find (delta t) with the equation:

delta t = [v^2(L1+L2)]/c^3

Derivation of this formula can be found in your physics text book. From here we find (delta t):

600,000^2 x (11+11) / [(3x10^8)^3] = 2.93x10^-13

2.93x10^-13/ (589x10^-9 / 3x10^8) = 149 fringes

This answer is correct but may seem large. That is because of your point of reference with the ether which is usually at rest with respect to the sun, making v = 3km/s.

4 0

4 years ago

which of the following cannot be determined by looking at the phase diagram? A. melting point, B. boiling point, C. subilmation

bulgar [2K]

I am pretty sure that <span>the following whihc cannot be determined by looking at the phase diagram is definitely </span>D. system pressure. I consider this one to be correct because only this point is not included into<span> phase diagram and can't be determined itself. Hope it will help! Regards!</span>

7 0

3 years ago

Mary and her younger brother Alex decide to ride the carousel at the State Fair. Mary sits on one of the horses in the outer sec

faltersainse [42]

Answer:

you can measure by scale beacause we dont no sorry i cant help u but u can ask me some other Q

6 0

3 years ago

During a practice shot put throw, the 7.9-kg shot left world champion C. J. Hunter's hand at speed 16 m/s. While making the thro

koban [17]

Answer:

a) a = 91.4 m / s², b) t = 0.175 s, c)

Explanation:

a) This is a kinematics exercise

v² = vox ² + 2a (x-xo)

a = v² - 0/2 (x-0)

let's calculate

a = 16² / 2 1.4

a = 91.4 m / s²

b) the shooting time

v = vox + a t

t = v-vox / a

t = 16 / 91.4

t = 0.175 s

c) let's use Newton's second law

F = ma

F = 7.9 91.4

F = 733 N

4 0

3 years ago