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VladimirAG [237]
3 years ago
9

What is the equation of the line perpendicular to –x + y = 7 and passing through (-1, -1)?

Mathematics
1 answer:
Vesna [10]3 years ago
6 0
- x + y = 7
y = x + 7
slope = 1
perpendicular slope = -1

at point (-1, -1),
y = mx + c
-1 = -1 (-1) + c
-1 = 1 + c 
c = -1 -1
c = - 2

equation:
y = -x -2
y + x = -2 or - x - y = 2
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jekas [21]

Given:

The figure of two parallel lines MP and QS.

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To find:

The m\angle KRQ.

Solution:

If a transversal line intersect the two parallel lines, then the corresponding angles are congruent and their measures are equal.

In the given figure \angle KRQ and \angle KNM corresponding angles. It means their measures are equal.

m\angle KRQ=m\angle KNM

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3 years ago
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Answer:

x = 15

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grandymaker [24]

Answer:

Heavenly,  we need the forumula for the area of a triangle, do you know it?

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then

A = 1/2* B * H

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use your algebra skillz  :P

20 = 1/2 *( b^{2} + 4b)

20*2 = b^{2} + 4b

40 = b^{2} + 4b

0 = b^{2} + 4b-40

rewrite the above so it's in x format

x^{2} + 4x -40 = 0

use the quadratic formula to find  x  , and for our problem, remember that x represents the base,  or b,  but don't mix it up with the b in the quadatic fomula,  with the b of the triangle, which is the base,  they are differnt "b"s   :P

X = (b±\sqrt{b^{2}-4*a*c } ) / 2*a

a = 1

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x = 2 + 6.633249 = 8.633

b= 8.633 cm

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