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dlinn [17]
2 years ago
9

We described numbers in this lesson using both powers of 10 and using standard decimal value. For example, the speed of light th

rough ice can be written as a multiple of a power of 10, such as (2.3)⋅108 meters per second, or as a value, such as 230,000,000 meters per second. Use the number line to answer questions about points A and B.
Describe point B as:

a. A multiple of a power of 10

Describe point A as:

a. A multiple of a power of 10
Mathematics
1 answer:
Ivanshal [37]2 years ago
5 0

Answer:

B = 2×10⁸

A = 3×10⁸

Step-by-step explanation:

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Suppose Cone A is similar to Cone B and the scale factor between the solids is 3:2, respectively. If the height of Cone A is 15
blondinia [14]

Answer:

10\ inches

Step-by-step explanation:

we know that

If two figures are similar, then the ratio of its corresponding sides is proportional

Let

x----> the height of cone B

using proportion

\frac{3}{2}=\frac{15}{x} \\ \\x=2*15/3\\ \\x=10\ in

4 0
3 years ago
The perimeter of a rectangular parking lot is 296 m if the width of the parking lot is 65 m , what is its length
Sophie [7]

Answer:

166

Step-by-step explanation:

So the width is 65, so two sides are each 65m long. So multiply 65*2 which is 130. this means that the other two sides need to equal 130 when added, so divide 130/2 which is 65

4 0
3 years ago
Read 2 more answers
I'm not exactly sure how to solve this or what the answer is. ​
arlik [135]

Answer:

9x^2-49

Step-by-step explanation:

FOIL

8 0
3 years ago
solve the system of equations by finding the reduced row-echelon form of the augmented matrix for the system of equations. x-2y+
Alekssandra [29.7K]

Answer:

x = -5, y = -6, z = -3

Step-by-step explanation:

Given the system of three equations:

\left\{\begin{array}{l}x-2y+3z=-2\\6x+2y+2z=-48\\x+4y+3z=-38\end{array}\right.

Write the augmented matrix for the system of equations

\left(\begin{array}{ccccc}1&-2&3&|&-2\\6&2&2&|&-48\\1&4&3&|&-38\end{array}\right)

Find the reduced row-echelon form of the augmented matrix for the system of equations:

\left(\begin{array}{ccccc}1&-2&3&|&-2\\6&2&2&|&-48\\1&4&3&|&-38\end{array}\right)\sim \left(\begin{array}{ccccc}1&-2&3&|&-2\\0&-14&16&|&36\\0&-6&0&|&36\end{array}\right)\sim \left(\begin{array}{ccccc}1&3&-2&|&-2\\0&16&-14&|&36\\0&0&-6&|&36\end{array}\right)

Thus, the system of three equations is

\left\{\begin{array}{r}x+3z-2y=-2\\16z-14y=36\\-6y=36\end{array}\right.

From the last equation:

y=-6

Substitute it into the second equation:

16z-14\cdot (-6)=36\\ \\16z=36-84\\ \\16z=-48\\ \\z=-3

Substitute y = -6 and z = -3 into the first equation:

x+3\cdot (-3)-2\cdot (-6)=-2\\ \\x=-2+9-12\\ \\x=-5

7 0
3 years ago
Help me out? tysvm!!!
Sophie [7]

Answer: 103

Step-by-step explanation:

8 x 6.5 = 52,

52 + 8 = 60 (pints in total)

there are 2 cups in 1 pint so 60 x 2 = 120

120 - 17 = 103

3 0
2 years ago
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