1. Galactosemia is a disease that will only be expressed when a person is<span><span><span> homozygotic recessive for that trait. It's the same as saying it </span> has</span> 2 recessive alleles.
Dominant allele-</span><span> G
recessive allele- g
</span>
Homozygotic dominant: GG <span><span>(doesn't express the disease)
</span>Heterozygotic : Gg (doesn't express the disease)
Homozygotic recessive: gg (expresses it)</span>
2.
-Mary has this genotype: G_ . This means it can be GG or Gg
-The exercise already says that justin's mother is GG (<span>Homozygotic dominant)
</span>- If his mother is GG, one of these G's is going to be passed to Justin. So, his genotype is either GG or Gg. Since we are not sure we write as: G_.
Justin's genotype: G_
3.
-Justin's uncle has galactosemia so his genotype is: gg
-If the uncle was able to receive two recessive alleles it means the mother had one to pass, and so did the father. However, in the diagram, it's not pointed out that they have a disease so it only leaves one possible genotype: Gg. Justin's grandparents are both Gg.
4. The last person to analyze is Justin's father.
If we crossed the grandparents (Gg x Gg) we could obtain these genotypes: GG, Gg, gg.
Justin's father doesn't express the trait, so it's not gg. That leaves us with either GG or Gg. Since we can't know for sure, onece again we write as G_
Justin's father: G_
Answer:
Explanation:Define as it relates to adaptation
Answer:
d
Explanation:
The answer would be d because limitation of models is basically about non realistic part of models that separate them from real life which is what d is saying.
Answer:
5.6L
Explanation:
Given parameters:
number of moles = 0.25mol
pressure on gas = 1atm
temperature = 273K
Gas constant R = 0.0821Latm/molK
Unknown:
Volume of gas = ?
Solution:
Using the ideal gas equation, we can solve this problem. The equation is a combination of the three gas laws: Boyle's law, Charles's law and Avogadro's law.
It is mathematically expressed as;
PV = nRT
where P is the pressure
V is the volume
R is the gas constant
T is the temperature
n is the number of moles
All the parameters are in the appropriate units and we simply solve for the volume of the gas;
1 x V = 0.25 x 0.0821 x 273
V = 5.6L