How does the reactivity of nonmetals change as you move from left to right across the periodic table?

PLEASE HELP!!!! Two science questions!!!! 20 points and brainliest!!!

Angelina_Jolie [31]

1. A cylinder is submerged in water as illustrated in the diagram. Which of the following statements is true?

The pressure at D is greater than at B. This is because D is trying to get back to the surface with an amount of pressure. B has less amount of pressure.

2. A cylinder is submerged in water as illustrated in the diagram. If the area of the top and the bottom of the cylinder is the same, which of the following statements is true?

buoyant force = (force D - force A).

Edit: If you ever notice. When you fill a sink full of water. Put a glass upside down and try forcefully to submerge it under the water it will resist. This is because of the pressure and air. The glass is less dense then water. (Also depends on the glass)

8 0

4 years ago

If the reaction N2 (g) + 3 H2 (g) --> 2 NH3 (g) has the concentrations 1.1 M for nitrogen, 0.75 M for hydrogen and 0.25 M fo

Luba_88 [7]

Answer: The value of $K_c$ is 0.136 and is reactant favored.

Explanation:

Equilibrium constant in terms of concentration is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as $K_{c}$

For the chemical reaction between carbon monoxide and hydrogen follows the equation:

$N_2(g)+3H_2(g)\rightleftharpoons 2NH_3(g)$

The expression for the $K_{c}$ is given as:

$K_{c}=\frac{[NH_3]^2}{[N_2][H_2]^3}$

We are given:

$[NH_3]=0.25M$

$[H_2]=0.75M$

$[N_2]=1.1M$

Putting values in above equation, we get:

$K_c=\frac{(0.25)^2}{1.1\times (0.75)^3}$

$K_c=0.135$

There are 3 conditions:

When $K_{c}>1$ ; the reaction is product favored.
When $K_{c}$ ; the reaction is reactant favored.
When $K_{c}=1$ ; the reaction is in equilibrium.

For the given reaction, the value of $K_c$ is less than 1. Thus, the reaction is reactant favored.

Hence, the value of $K_c$ is 0.136 and is reactant favored.

4 0

3 years ago

What is calculated by dividing mass volume

dem82 [27]

By dividing mass with volume, you will end up with density

7 0

3 years ago

What determines the types of chemical reactions that an atom participates in?

nikklg [1K]

Answer:

The innermost electron shell of an atom can hold up to _____ electrons. ... What determines the types of chemical reactions that an atom participates in? the number of electrons in the outermost electron shell. Atoms with the same number of protons but with different electrical charges

7 0

3 years ago

What is the standard cell notation for a galvanic cell made with silver and nickel?

MA_775_DIABLO [31]

Answer:

Ni(s)∣∣Ni2+(aq) ∣∣∣∣ Ag+(aq)∣∣Ag(s)

Explanation:

Start by finding the standard reduction potential for the Ag+ and Ni2+ ion. Normally, the values are listed at the back of most chemistry textbooks.

Ag+(aq)+1e−→Ag(s) Eo=0.80 V
Ni2+(aq)+2e−→Ni(s) Eo=−0.23 V

In the galvanic cell, the reaction is spontaneous and for a spontaneous reaction Eocellmust be a positive quantity.

Eocell=EoAnode+Eocathode

Manipulate the two equations so that Eocell is positive. Note that the anode is the site of oxidation (where electrons are lost) and the cathode (where electron are gained) is the site for reduction.

Ag+(aq)+1e−→Ag(s) Eo=0.80 V
Ni(s)→Ni2+(aq)+2e− Eo=0.23 V

2×{Ag+(aq)+1e−→Ag(s)} Eo=0.80 V (Cathode)
Ni(s)→Ni2+(aq)+2e− Eo=0.23 V (Anode)
 −−−
2Ag+(aq)+Ni(s)→Ni2+(aq)+2Ag(s) Eocell=1.03 V

Start with the anode components (site of oxidation) - the cathode components are listed to the right.

Ni(s)∣∣Ni2+(aq) ∣∣∣∣ Ag+(aq)∣∣Ag(s)

The single vertical lines indicate the boundary (phase difference) between solid Niand Ni2+ ions in the aqueous solution of the first compartment and between solid Ag and Ag+ ions present in the aqueous solution of the second compartments.

The double vertical lines refer to the salt bridge - note that the salt bridge must be an inert salt to both ions present in both compartments of the galvanic cell ...

5 0

3 years ago