Answer:
The answer to your question is 58.5 g of NaCl
Explanation:
Data
mass of NaCl = ?
mass of HCl = 40 g
mass of NaOH = 40 g
Balanced chemical reaction
HCl + NaOH ⇒ H₂O + NaCl
-Calculate the molar mass of the reactants
HCl = 1 + 35.5 = 36.5 g
NaOH = 23 + 16 + 1 = 40 g
-Calculate the limiting reactant
theoretical proportion = HCl/NaOH = 36.5 / 40 = 0.9125
experimental proportion = HCl / NaOH = 40 / 40 = 1
As the experimental proportion was higher than the theoretical proportion, the limiting reactant is NaOH.
-Calculate the molar mass of NaCl
NaCl = 23 + 35.5 = 58.5
-Calculate the experimental mass of NaCl
40 g of NaOH -------------------- 58.5 g of NaCl
40 g of NaOH ------------------- x
x = (40 x 58.5) / 40
x = 58.5 g of NaCl
I believe the correct answer from the choices listed above is option B. Atmospheric pressure yesterday was given as 0.875 atm. Converting this value in units of torr and kPa would yield into 665 torr and 88.7 kPa. Hope this answers the question. Have a nice day.
Observe the movment of other planets would be your answer
Answer:
to protect peoples teeth against cavities
Explanation:
i just know
Answer:
0.0827M of H₂SO₃
Explanation:
LiOH reacts with H₂SO₃ to produce water and Li₂SO₃, thus:
2LiOH + H₂SO₃ → 2H₂O + Li₂SO₃
<em>Where 2 moles of lithium hydroxide react with 1 mole of sulfurous acid.</em>
As the chemist requires 22.14mL = 0.02214L of a 0.210M solution to neutralize the acid, moles of LiOH are:
0.02214L × (0.210mol / L) =<em>0.004649 moles of LiOH</em>.
As 2 moles of LiOH react with 1 mole of H₂SO₃, moles of H₂SO₃ are:
0.004649 moles of LiOH ₓ (1 mole H₂SO₃ / 2 mol LiOH) =
<em>0.002325 moles of H₂SO₃</em>
These moles are present in 28.10mL = 0.02810L. Thus, molar concentration of the acid is:
0.002325 moles H₂SO₃ / 0.02810L = <em>0.0827M of H₂SO₃</em>