The molar mass of methylammonium bromide is 111u.
<h3>What is molar mass?</h3>
The molar mass is defined as the mass per unit amount of substance of a given chemical entity.
Multiply the atomic weight (from the periodic table) of each element by the number of atoms of that element present in the compound.
Add it all together and put units of grams/mole after the number.
Atomic weight of H is 1u
Atomic weight of N is 14u
Atomic weight of C is 12u
Atomic weight of Br is 79u
Calculating molar mass of 
=2(1 x3+ 14+12+ 1 x 3 +79) = 111u
Hence, the molar mass of methylammonium bromide is 111u.
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Answer: isotopes
Explanation: I remember this from when I took honors chemistry, they are know as isotopes.
Answer:
Changing the volume increases the area that the molecules collide with so the force is spread over a larger area.
Explanation:
The volume of a container is the space within the container. This is the amount of void the gas can occupy.
When the volume of a container is changed, the space either increases or decreases.
- An increase in volume creates more space within the container.
- This spreads out the force over a larger area.
When the volume of the container is reduced,
- the force is confined to much smaller space.
The frequency of collision is higher for tiny spaces.
But lower for a large volume.
Answer:
Concentration of the sugar in the solution increases
Answer:
1.57 mol NaN₃
Explanation:
- 2 NaN₃ (s) → 2 Na (s) + 3 N₂ (g)
First we <u>use PV=nRT to calculate the number of N₂ moles that need to be produced</u>:
- R = 0.082 atm·L·mol⁻¹·K⁻¹
- T = 23.7 °C ⇒ 23.7 + 273.16 = 296.86 K
<u>Inputing the data</u>:
- 1.07 atm * 53.4 L = n * 0.082 atm·L·mol⁻¹·K⁻¹ * 296.86
And <u>solving for n</u>:
Finally we <u>convert N₂ moles into NaN₃ moles</u>, using <em>the stoichiometric coefficients of the balanced reaction</em>:
- 2.35 mol N₂ *
= 1.57 mol NaN₃
