According to the periodic table, which two elements are in the same row?

The amount of heat involved in the synthesis of 1 mole of a compound from its elements, with all substances in their standard st

kvasek [131]

Given:

1 mole of compound synthesized from its elements
Temperature of the substances in their standard states = 25 degrees Celcius

First, gather data from reference books on the standard heats of formation of the elements. Then set up a balanced equation for the reaction. From there, calculate the heat of reaction.

4 0

3 years ago

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Can you please solve this. ..above question

Dennis_Churaev [7]

Answer:

(dont know if this is correct took this last year)

Explanation:

1 hydrogen atom plus 1 chlorine atom is equal to 2 hydrochloric acids due to the fact that there are 2 atoms in both substances and the equation has to stay constant throughout according to the law of conservation of mass

same goes for 2 sulfate atoms and 3 oxygen atoms

in order to balance this this the sulfate atoms have to take into account that their are 2 sulfate atoms and 6 oxygen atoms so you have to add more sulfates to make them both equal 6 then balance it with the oxygens

6 0

4 years ago

Write a balanced half-reaction for the reduction of gaseous oxygen to aqueous hydrogen peroxide in basic aqueous solution. Be su

Vesna [10]

Answer:

Balanced half-reaction: $O_{2}(g)+2H_{2}O(l)+2e^{-}\rightarrow H_{2}O_{2}(aq.)+2OH^{-}(aq.)$

Explanation:

Balanced half-reaction for the reduction of gaseous oxygen to aqueous hydrogen peroxide in basic solution should be written in the following step-by-step manner:

Half-reaction: $O_{2}(g)\rightarrow H_{2}O_{2}(aq.)$

Balance H and O in basic medium: $O_{2}(g)+2H_{2}O(l)\rightarrow H_{2}O_{2}(aq.)+2OH^{-}(aq.)$

Balance charge: $O_{2}(g)+2H_{2}O(l)+2e^{-}\rightarrow H_{2}O_{2}(aq.)+2OH^{-}(aq.)$

Balanced half-reaction: $O_{2}(g)+2H_{2}O(l)+2e^{-}\rightarrow H_{2}O_{2}(aq.)+2OH^{-}(aq.)$

7 0

4 years ago

Which statement is part of the kinetic molecular theory?

Tcecarenko [31]

Answer:Option A

Explanation:

4 0

3 years ago

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A certain first-order reaction (A→products) has a rate constant of 7.20×10−3 s−1 at 45 ∘C. How many minutes does it take for the

lesya692 [45]

Answer:

6,41 min

Explanation:

For the reaction:

A → products

kinetics first-order reaction law is:

ln[A] = ln[A]₀ -kt

Where [A] is concentration of reactant, [A]₀ is initital concentration of reactant, k is rate constant and t is time.

If the concentration of A is 6,25% you can assume:

[A] = 6,25; [A]₀= 100. Replacing:

ln(6,25) = ln(100) -7,20×10⁻³s⁻¹t

-2,7726 = -7,20×10⁻³s⁻¹t

385s = t

In minutes:

385s× $\frac{1min}{60s}$ = <em>6,41 min</em>

I hope it helps!

6 0

3 years ago