Dont quote me here, I would do some more research. but I think its oblique lighting. I'm trying to remember but im not fully sure :) sorry if im wrong
Answer:
Q ≈ 1 x 10⁵ joules (1 sig. fig. based on 50g sample given)
Explanation:
Three heat transitions need be considered. Cooling the steam to 100°C, condensing the steam to water and cooling the water from 100°C to 87°C.
Total Heat exchange (Q) = ∑ heat transitions
Q = (m·c·ΔT)steam + (m·ΔH)condensation + (m·c·ΔT)water cooling
= (50g x 0.48j/g·°C x 14°C) + (50g x 2259j/g) + (50g x 4.184j/g·°C)
= 24j + 112,950j + 209.2j
= 113,183.2j ≈ 1 x 10⁵ joules (1 sig. fig. based on 50g sample given)
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Actually Welcome to the concept of Atomic Structure.
Since, We all know that, To draw any Electron-Dot Structure, we always have to know the exact Number of valence or free electrons of any atom or molecule, hence
The Correct Answer is :-
D. Number of valence electrons.
C6H6 + 15/2O2 = 6CO2 + 3H2O/×2
2C6H6 + 15O2 = 12CO2 + 6H2O