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Sergio [31]
3 years ago
14

Jorge has an unknown mineral. The mineral has a mass of 21 grams and has a volume of 3cm3. Calculate density and find his unknow

n material
Chemistry
1 answer:
DerKrebs [107]3 years ago
6 0

Answer:

7g/cm³

Explanation:

Given parameters:

Mass of the mineral  = 21g

Volume  = 3cm³

Unknown:

Density of the mineral  = ?

Solution:

Density of a substance is the mass per unit volume of the substance.

 Density  = \frac{mass}{volume}  

  Now insert the given parameters and solve;

  Density  = \frac{21}{3}   = 7g/cm³

The mineral with a density of 7g/cm³ is Galena, an ore of lead.

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Comppare and contrast sexual reproucton and asexual repructon
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Answer:

Asexual reproduction involves only 1 parent. The daughter cells / offspring are the exact clones of the parent. There’s no variety. The end products are only 2 daughter cells. Sexual reproduction involves 2 parents (a mate). The offspring consists of a mixture of genes from both parents. There’s more variety to the offspring. 4 daughter cells are produced in sexual reproduction. Both undergo cell division. Asexual reproduction = mitosis Sexual reproduction = meiosis. Sexual reproduction produces the gametes, asexual produces body cells

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3 years ago
How many atoms of oxygen is in CO2?
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3 years ago
What mass of ice can be melted with the same quantity of heat as required to raise the temperature of 3.00 mol H2O(l) by 50.0°C?
lions [1.4K]

Answer:

m=33.9g

Explanation:

Hello,

In this case, we can first compute the heat required for such temperature increase, considering the molar heat capacity of water (75.38 J/mol°C):

Q=nCp \Delta T=3.00mol*75.38\frac{J}{mol\°C} *50.0\°C\\\\Q=11307J

Afterwards, the mass of ice that can be melted is computed by:

Q=n \Delta _{fus}H

So we solve for moles with the proper units handling:

n=\frac{Q}{\Delta _{fus}H} =\frac{11307J}{6010\frac{J}{mol} } =1.88mol

Finally, with the molar mass of water we compute the mass:

m=1.88mol*\frac{18g}{1mol}\\ \\m=33.9g

Best regards.

7 0
3 years ago
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