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SOVA2 [1]
3 years ago
9

What is the simplest form of i^15

Mathematics
1 answer:
Korolek [52]3 years ago
4 0

Answer: -iSimplify the expression using the definition of an imaginary number  

i = √ − 1 . − i

Step-by-step explanation: Simplify the expression using the definition of an imaginary number i = √ − 1 . − i

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TOOS
Eddi Din [679]

Answer:

Step-by-step explanation:

Given that:

Number of books, b α number of children enrolled

b α C

b = kC

Number of books, b = 3 for each child, c = 1 enrolled

Total number of books in class room :

Total number of books = Number of books per child * Number of child)

Total number of books = 3 * Numbe of child

7 0
3 years ago
Read 2 more answers
tres cajas contienen cuatrocientas naranjas la primera tiene veinte naranjas mas q la segunda y treinta mas q la tercera cuantas
Lemur [1.5K]

Answer: Box3 has 120 oranges.

Box1 has 150 oranges.

Box  has 130 oranges.

Step-by-step explanation:

I will answer this in English.

The question says:

3 boxes have 400 oranges.

The first one has 20 more than the second and 30 more than the third.

So we have 3 equations:

box1 + box2 + box3 = 400

box1 = box2 + 20

box1 = box3 + 30

Now, we can take the variable box1 in the third equation and replace it on the other two.

box3 + 30 + box2 + box3 = 400

box3 + 30 = box2 + 20

Now we can isolate one of the variables in the second equation, let's isolate box2.

box2 = box3 + 30 - 20 = box3 + 10

now we can replace it in the other equation:

box3 + 30 + box2 + box3 = 400

box3 + 30 + box3 + 10 + box3 = 400

3*box3 + 40 = 400

3*box3 = 400 - 40 = 360

box3 = 360/3 = 120.

Box3 has 120 oranges.

Box1 has 120 + 30 = 150 oranges.

Box  has 150 - 20 = 130 oranges.

5 0
3 years ago
Pleae help thanks a bunch
zloy xaker [14]
Hello!

You use the Pythagorean theorem to solve this

a^{2} + b^{2} = c^{2}

Put in the values it tells you to

a^{2} + 4.4^{2} = 5.5^{2}

Square the numbers

a^{2} + 19.36 = 30.25

Subtract 19.36 from both sides

a^{2} = 10.89

Take the square root of both sides

a = 3.3

The answer is 3.3

Hope this helps!
8 0
2 years ago
The value of (a-1)+a^2-b^2/1-ab+2(a-b)/2b when a=2 and b=-1 is ?
poizon [28]
<span>The value of (a-1)+a^2-b^2/1-ab+2(a-b)/2b when a=2 and b=-1 will be evaluated as follows:
substituting the values in the expression we obtain:
(2-1)+2^2-(-1)^2/1-(2*(-1))+2(2-(-1))/(2(-1))
simplifying the above we get:
1+4-1/1-(-2)+2(2+1)/(-2)
=1+4-1+2(3)/(-2)
=1+4-1-3
=5-4
=1

Answer: 1</span>
8 0
3 years ago
What is the answer to -3x - 6+ (-1)​
IrinaK [193]

Answer:

-3x-7

Step-by-step explanation:

6 0
3 years ago
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