Answer:
Car A has a velocity of 40 km/hr west.
Explanation:
The velocity of an object is a vector quantity. It has both magnitudes as well as direction.
Arrows are used to show direction.
Car A is moving towards west. Car B is moving towards east-south direction. Car C is moving towards South direction. Car E is moving towards North direction.
So, the correct option is (a) i.e. Car A has a velocity of 40 km/hr west.
Answer:
B. False
A concave mirror and a converging lens will only produce a real image if the object is located beyond the focal point.
~Hoped this helped~
~Brainiliest?~
Here is the missing information.
An exhausted bicyclist pedal somewhat erraticaly when exercising on a static bicycle. The angular velocity of the wheels takes the equation ω(t)=at − bsin(ct) for t≥ 0, where t represents time (measured in seconds), a = 0.500 rad/s2 , b = 0.250 rad/s and c = 2.00 rad/s .
Answer:
0.793 rad
Explanation:
From the given question:
The angular velocity of the wheel is expressed by the equation:
The angular velocity of the wheels takes the description of the equation ω(t)=at−bsin(ct)
SO;
dθ = at dt - (b sin ct) dt
Taking the integral of the above equation; we have:
where;
a = 0.500 rad/s2 ,
b = 0.250 rad/s and
c = 2.00 rad/s
Hence, the angular displacement after two seconds = 0.793 rad
Answer:
Explanation:
Work in pumping water from the tank is given as
W = ∫ y dF. From a to b
Where dF is the differential weight of the thin layer of liquid in the tank, y is the height of the differential layer
a is the lower limit of the height
b is the upper limit of the height.
We know that, .
F = ρVg
Where F is the weight
ρ is the density of water
V is the volume of water in tank
g is the acceleration due to gravity
Then,
dF = ρg ( Ady)
We know that the density and the acceleration due to gravity is constant, also the base area of the tank is constant, only the height that changes.
Then,
ρg = 62.4 lbs/ft³
Area = L×B = 3 × 9 = 27ft²
dF = ρg ( Ady)
dF = 1684.8dy
The height reduces from 12ft to 0ft
Then,
W = ∫ y dF. From a to b
W = ∫ 1684.8y dy From 0 to 12
W = 1684.8y²/2 from 0 to 12
W = 842.4 [y²] from y = 0 to y = 12
W = 842.4 (12²-0²)
W = 121,305.6 lb-ft
the C stands for Consistent