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3 years ago

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Let the acceleration of a particle be given by a(t)=t-1. the initial velocity is v(0)=10. find v(5). what is the displacement of

the particle in between t=0 and t=5

1 answer:

Natalka [10]3 years ago

3 0

Here, check this out.

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When a spring is compressed, the energy changes from kinetic to potential. Which best describes what is causing this change?

just olya [345]

Answer:

<em>Well, Your answer will be is </em><em>Work. </em><em>Because, When a spring is compressed, the energy changes from kinetic to potential. This change is caused by work. </em>

<em>Good Luck!~</em>

$^{By$ $^{Itsbrazts$

6 0

4 years ago

Read 2 more answers

A concrete slab shown in Figure 5 is being lifted by using three cables connected to the slab at points A, B and C. The slab is

xxMikexx [17]

Answer:

Fad = 28.8 kN

Fbd = 16.4 kN

Fcd = 28.1 kN

Explanation:

First, find the length of each cable.

AD = √((2 m)² + (0.5 m)² + (2.5 m)²)

AD = √10.5 m

AD ≈ 3.24 m

BD = √((1.5 m)² + (1 m)² + (2.5 m)²)

BD = √9.5 m

BD ≈ 3.08 m

CD = √((1 m)² + (1 m)² + (2.5 m)²)

CD = √8.25 m

CD ≈ 2.87 m

Next, use similar triangles to find the x, y, and z components of each tension force.

Fadx = 2/3.24 Fad = 0.617 Fad

Fady = 0.5/3.24 Fad = 0.154 Fad

Fadz = 2.5/3.24 Fad = 0.772 Fad

Fbdx = 1.5/3.08 Fbd = 0.487 Fbd

Fbdy = 1/3.08 Fbd = 0.324 Fbd

Fbdz = 2.5 / 3.08 Fbd = 0.811 Fbd

Fcdx = 1/2.87 Fcd = 0.348 Fcd

Fcdy = 1/2.87 Fcd = 0.348 Fcd

Fcdz = 2.5/2.87 Fcd = 0.870 Fcd

Now sum the forces in the x, y, and z directions:

∑Fx = ma

-0.617 Fad + 0.487 Fbd + 0.348 Fcd = 0

∑Fy = ma

-0.154 Fad − 0.324 Fbd + 0.348 Fcd = 0

∑Fz = ma

60 kN − 0.772 Fad − 0.811 Fbd − 0.870 Fcd = 0

To solve this system of equations algebraically, start by subtracting the first two equations, eliminating Fcd.

-0.463 Fad + 0.811 Fbd = 0

0.811 Fbd = 0.463 Fad

Fbd = 0.571 Fad

Substitute into either of the first two equations:

-0.617 Fad + 0.487 (0.571 Fad) + 0.348 Fcd = 0

-0.617 Fad + 0.278 Fad + 0.348 Fcd = 0

-0.339 Fad + 0.348 Fcd = 0

0.348 Fcd = 0.339 Fad

Fcd = 0.975 Fad

Now substituting into the third equation:

60 kN − 0.772 Fad − 0.811 Fbd − 0.870 Fcd = 0

60 kN − 0.772 Fad − 0.811 (0.571 Fad) − 0.870 (0.975 Fad) = 0

60 kN − 0.772 Fad − 0.463 Fad − 0.849 Fad = 0

60 kN − 2.083 Fad = 0

Fad = 28.8 kN

Solving for the other two tension forces:

Fbd = 0.571 Fad = 16.4 kN

Fcd = 0.975 Fad = 28.1 kN

3 0

3 years ago

Read 2 more answers

Please need help with this

Mademuasel [1]

A 'velocity' is built out of a speed and a direction.

The only item on that list that has a speed and a direction is the <em>first one</em>. The speed is 30 m/s and the direction is south.

8 0

4 years ago

A 48.5 kg student runs down the sidewalk and jumps with a horizontal speed of 4.25 m/s onto a stationary skateboard. The student

storchak [24]

<u>Answer:</u>

2.39 kg

<u>Explanation:</u>

There is conservation of momentum here in this problem so we will use the following problem:

$m_1u_1+m_2u_2=(m_1+m_2)v$

where the mass of the student $m_1$ is 48.5 kg,

the mass of the skateboard $m_2$ is $m_2$ kg,

the initial speed of the student $u_1$ is 4.25 m/s; and

the speed of the student and skateboard $v$ is 4.05 m/s.

So substituting the given values in the above formula to get:

$(48.5*4.25) + (m_2 * 0) = (48.5 + m_2 ) * 4.05$

$206.125=196.425+4.05m_2$

$206.125 - 196.425 = 4.05m_2$

$m_2=\frac{9.7}{4.05}$

$m_2=2.39$

Therefore, the mass of the skateboard is 2.39 kg.

7 0

3 years ago

The velocity field of a flow is given by V = 3x2ti+[4y(t-1)+3x2t] j m/s, where x and y are in meters and t is in seconds. For fl

Katena32 [7]

Answer:

See explanations

Explanation:

Given that,

Electric field E=135V/m

Energy stored in 1m³of air=?

The energy stored in an electric field is given as

u = ½ εo E²

Where

U is the energy stored

εo is permissivity and it value is 8.85×10^-12C²/N..m²

And E is the electric field

Then,

U=½×8.85×10^-12×135²

U=8.06×10^-8J/m³

Then, the energy stored in 1m³ of air is 8.06×10^-8 J/m³

6 0

3 years ago