Let the acceleration of a particle be given by a(t)=t-1. the initial velocity is v(0)=10. find v(5). what is the displacement of
the particle in between t=0 and t=5
1 answer:
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We have:
Total Energy: KE + GPE
KE (Kinetic Energy) =
GPE (Gravitational Potential Energy) =
Data:
m (mass) = 2.0 Kg
v (speed) = 10 m/s
h (height) = 50 m
Use: g (gravity) = 10 m/s²
Formula:
Total Energy: KE + GPE
Solving:
Total Energy: KE + GPE
KE (Kinetic Energy) =
GPE (Gravitational Potential Energy) =
Data:
m (mass) = 2.0 Kg
v (speed) = 10 m/s
h (height) = 50 m
Use: g (gravity) = 10 m/s²
Formula:
Total Energy: KE + GPE
Solving: