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3 years ago

Explain how the weight of an object is an application of newton's second law

1 answer:

4 0

Weight is a measure of the force of gravity acting on an object. According to Newton’s laws of motion, force is directly proportional to both mass and acceleration, and the equation for force is F=m*a, where m is mass and a is acceleration. We can use this equation to solve for weight.

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If you drop a bowling ball, a tennis ball, and a feather from the top of a tall building at the same time, which one will hit th

olasank [31]

They hit at the same time. Everything falls at the same rate.

8 0

3 years ago

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(II) A 1200-kg car moving on a horizontal surface has speed v = 85 km/h when it strikes a horizontal coiled spring and is brough

Pie

Answer:

k = 138440 N/m

Explanation:

given,

Mass of the car = 1200 Kg

speed of the car = 85 km/h

= 85 x 0.278 = 23.63 m/s

KE of the car

$KE = \dfrac{1}{2} mv^2$

Using Spring Energy Formula

$KE_{spring}=\dfrac{1}{2}kx^2$

Using conservation of energy

$\dfrac{1}{2} mv^2=\dfrac{1}{2}kx^2$

$k = \dfrac{mv^2}{x^2}$

$k = \dfrac{1200\times 23.63^2}{2.2^2}$

k = 138440 N/m

Spring stiffness constant of the spring is equal to k = 138440 N/m

7 0

3 years ago

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charle [14.2K]

Answer:

ANSWER

A = 5 cm = 0.05 m

T = 0.2 s

ω=2π/T=2π/0.2=10πrad/s

plz give brainlist

hope this helped

3 0

3 years ago

A tuning fork vibrates at 15,660 oscillations every minute. What is the period (in seconds) of one back and forth vibration of t

Ierofanga [76]

We are given:

The tuning fork vibrates at 15660 oscillations per minute

Period of one back-and forth movement:

the given data can be rewritten as:

1 minute / 15660 oscillations

60 seconds / 15660 oscillations (1 minute = 60 seconds)

dividing the values

0.0038 seconds / Oscillation

Therefore, one back and forth vibration takes 0.0038 seconds

4 0

3 years ago

What is the period of a water wave if 4.0

aev [14]

We are told that 4.0 complete waves pass a fixed point in 10 seconds. Using these data, we can find the frequency of the wave, which is given by the number of complete cycles per second:

$f=\frac{N}{t}=\frac{4}{10 s}=0.4 Hz$

Now we can find the period of the wave, which is the reciprocal of the frequency:

$T=\frac{1}{f}=\frac{1}{0.4 s}=2.5 Hz$

So, the correct answer is (3) 2.5 s.

6 0

3 years ago

Read 2 more answers