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dlinn [17]
2 years ago
12

How does freezing and evaporation affect salinity? Choose ALL that apply Lesson 2.05 When that water melts in the spring, the sa

linity decreases. none of the choices When ocean water evaporates, the salinity increases. When ocean water freezes, the salinity of water increases.​
Chemistry
1 answer:
V125BC [204]2 years ago
5 0

1. When that water melts in the Spring, the salinity decreases.

2.  When ocean water evaporates, the salinity increases.

3. When ocean water freezes, the salinity of water increases.

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Write a hypothesis using IF-THEN - BECAUSE of statement. (PLEASE HELP)
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3 0
2 years ago
The type of radiation which is identical to a high energy electron is known as a(n). beta, alpha, or gamma particles
Schach [20]
The type of radiation which is identical to a high energy electron is known as a(n) beta.

Answer: A) or the first option.
5 0
3 years ago
Read 2 more answers
The specific heat for liquid ethanol is 2.46 J/(g•°C). When 210 g of ethanol is cooled from
avanturin [10]

Answer:

a) heat it from 23.0 to 78.3

q = (50.0 g) (55.3 °C) (2.46 J/g·°C) =  

b) boil it at 78.3

(39.3 kJ/mol) (50.0 g / 46.0684 g/mol) =  

c) sum up the answers from the two calculations above. Be sure to change the J from the first calc into kJ

Explanation:

3 0
2 years ago
Which combination(s) of alkyl bromide and carbonyl compound can be used to prepare the following product by reaction of the Grig
Fiesta28 [93]

Answer:

D. only 2 and 3

Explanation:

The Grignard compound or reagent is a highly reactive compound formed from the reaction between an ether solvent containing magnesium and a haloalkane. This compound can also be used to create a C-C bond (carbon-carbon). Based on the properties and structure of a Grignard compound, the answer is option D.

7 0
2 years ago
The concentration of Rn−222 in the basement of a house is 1.45 × 10−6 mol/L. Assume the air remains static and calculate the con
bonufazy [111]

<u>Answer:</u> The concentration of radon after the given time is 3.83\times 10^{-30}mol/L

<u>Explanation:</u>

All the radioactive reactions follows first order kinetics.

The equation used to calculate half life for first order kinetics:

t_{1/2}=\frac{0.693}{k}

We are given:

t_{1/2}=3.82days

Putting values in above equation, we get:

k=\frac{0.693}{3.82}=0.181days^{-1}

Rate law expression for first order kinetics is given by the equation:

k=\frac{2.303}{t}\log\frac{[A_o]}{[A]}

where,  

k = rate constant = 0.181days^{-1}

t = time taken for decay process = 3.00 days

[A_o] = initial amount of the reactant = 1.45\times 10^{-6}mol/L

[A] = amount left after decay process =  ?

Putting values in above equation, we get:

0.181days^{-1}=\frac{2.303}{3.00days}\log\frac{1.45\times 10^{-6}}{[A]}

[A]=3.83\times 10^{-30}mol/L

Hence, the concentration of radon after the given time is 3.83\times 10^{-30}mol/L

7 0
3 years ago
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