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dlinn [17]
3 years ago
12

How does freezing and evaporation affect salinity? Choose ALL that apply Lesson 2.05 When that water melts in the spring, the sa

linity decreases. none of the choices When ocean water evaporates, the salinity increases. When ocean water freezes, the salinity of water increases.​
Chemistry
1 answer:
V125BC [204]3 years ago
5 0

1. When that water melts in the Spring, the salinity decreases.

2.  When ocean water evaporates, the salinity increases.

3. When ocean water freezes, the salinity of water increases.

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Naturally occurring zirconium exists are five isotopes. axe with a mass of 89.905 u(51.45%); Zr with a mass of 90.906 u (11.22%)
Anton [14]
Isotope 1: 89.905 * 51.45 = 4625.61225 / 100 = 46.2561225
Isotope 2: 90.906 * 11.22 = 1019.96532 / 100 = 10.1996532
Isotope 3: 91.905 * 17.15 = 1576.17175 / 100 = 15.7617075
Isotope 4: 93.906 * 17.38 = 1632.08628 / 100 = 16.3208628
Isotope 5: 95.908 * 2.08 = 268.5424 / 100 = 2.685424

46.2561225 + 10.1996532 +  15.7617075 + 16.3208628 + 2.685424 = 91.22377
actual mass Zr = about 91.22
8 0
3 years ago
g How many turns through the citric acid cycle are required to fully oxidize all of the acetly-coA that result from 1 molecule o
faust18 [17]

Answer:

The two molecules of acetyl-CoA that are produced from a molecule of glucose goes through two turn in the citric acid cycle, one for each molecule of acetyl-CoA.

Explanation:

Glycolysis the process by which a molecule of glucose is broken down in a series of steps to yield two molecules of pyruvate. The overall equation for  the reactions of glycolsis is given below:

Glucose + 2NAD+ ----> 2 Pyruvate + 2NADH + 2H⁺

Each of the two pyruvate molecules produced from glucose breakdown is further oxidized to two molecules of acetyl-CoA and CO₂ each.

2 Pyruvate ----> 2 AcetylCoA + 2CO₂

Each of the acetyl-CoA molecule then enters the citric acid cycle for its oxidation. In each turn of the cycle, one acetyl group enters as acetyl-CoA and two molecules of CO₂ leave.

7 0
3 years ago
The temperature of a 95.4 g piece of Cu increases from 25.0 °C to 48.0 °C when the Cu absorbs 849 J of heat. What is the specifc
melisa1 [442]
<h3>Answer:</h3>

0.387 J/g°C

<h3>Explanation:</h3>
  • To calculate the amount of heat absorbed or released by a substance we need to know its mass, change in temperature and its specific heat capacity.
  • Then to get quantity of heat absorbed or lost we multiply mass by specific heat capacity and change in temperature.
  • That is, Q = mcΔT

in our question we are given;

Mass of copper, m as 95.4 g

Initial temperature = 25 °C

Final temperature = 48 °C

Thus, change in temperature, ΔT = 23°C

Quantity of heat absorbed, Q as 849 J

We are required to calculate the specific heat capacity of copper

Rearranging the formula we get

c = Q ÷ mΔT

Therefore,

Specific heat capacity, c = 849 J ÷ (95.4 g × 23°C)

                                        = 0.3869 J/g°C

                                        = 0.387 J/g°C

Therefore, the specific heat capacity of copper is 0.387 J/g°C

3 0
3 years ago
When aqueous solutions of potassium carbonate and cobalt(II) sulfate are combined, solid cobalt(II) carbonate and a solution of
Lostsunrise [7]
K2CO3 (aq) + CoSO4 (aq) ---> CoCO3 (s) + K2SO4 (aq)
6 0
3 years ago
Read 2 more answers
How many milliliters of .085 m naoh are required to titrate 25 ml of .072 m hbr to the equivalence point?
SOVA2 [1]
The ML  of 0.85  m NaOH    required   to  titrate  25 ml of  0.72m hbr  to  the  equivalence  point  is calculated  as  follows

calculate  the moles  of HBr used

moles  = molarity  x  volume

25  x0.072/1000=  0.0018 moles


write the  equation  for  reaction

NaOH + HBr = NaBr  +  H2O
from   reacting   equation the  mole ratio  between  NaOH  to  HBr  is  1:1  therefore  the  moles of  NaOH  =  0.0018 moles

volume   =  moles/molarity
0.0018/0.085 =  0.021  L  in Ml  =  0.021  x1000=21.18 Ml  ofNaOH

8 0
3 years ago
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