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dlinn [17]
3 years ago
12

How does freezing and evaporation affect salinity? Choose ALL that apply Lesson 2.05 When that water melts in the spring, the sa

linity decreases. none of the choices When ocean water evaporates, the salinity increases. When ocean water freezes, the salinity of water increases.​
Chemistry
1 answer:
V125BC [204]3 years ago
5 0

1. When that water melts in the Spring, the salinity decreases.

2.  When ocean water evaporates, the salinity increases.

3. When ocean water freezes, the salinity of water increases.

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A warm ocean transfers heat to the air above it. Which type of heat transfer is this
Zigmanuir [339]

Answer:

Conduction

Explanation:

Because When air is  in contact with the ocean it is at a different temperature than the seas surface

7 0
3 years ago
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Calculate the ph of a 0.021 m nacn solution. [ka(hcn) = 4.9  10–10]
ohaa [14]

<span>Answer is: pH of solution of sodium cyanide is 11.3.
Chemical reaction 1: NaCN(aq) → CN</span>⁻(aq) + Na⁺<span>(aq).
Chemical reaction 2: CN</span>⁻ + H₂O(l) ⇄ HCN(aq) + OH⁻<span>(aq).
c(NaCN) = c(CN</span>⁻<span>) = 0.021 M.
Ka(HCN) =  4.9·10</span>⁻¹⁰<span>.
Kb(CN</span>⁻) = 10⁻¹⁴ ÷ 4.9·10⁻¹⁰ = 2.04·10⁻⁵<span>.
Kb = [HCN] · [OH</span>⁻] / [CN⁻<span>].
[HCN] · [OH</span>⁻<span>] = x.
[CN</span>⁻<span>] = 0.021 M - x..
2.04·10</span>⁻⁵<span> = x² / (0.021 M - x).
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pH = 14 - 2.70 = 11.3.</span>

4 0
2 years ago
A solution is prepare using 45.2 g of an unknown (nonelectrolyte) dissolved in 476.4 g of water. The freezing point depression
Ray Of Light [21]

Answer:

94.4g/mol is molar mass of the unknown

Explanation:

Based on the freezing point depression equation:

ΔT = Kf*m*i

<em>Where ΔT is the depression in freezing point (1.87°C)</em>

<em>Kf is freezing point depression constant of water (1.86°Ckg/mol)</em>

<em>And i is Van't Hoff factor (1 for nonelectrolyte solutes)</em>

<em />

Replacing:

1.87°C = 1.86°CKg/mol*m*i

1.005mol/kg solvent = m

Using the mass of the solvent we can find the oles of the nonelectrolyte:

1.005mol/kg solvent * 0.4764kg = 0.479moles

Molar mass is defined as the ratio between mass of a substance in grams and moles, that is:

45.2g / 0.479mol =

<h3>94.4g/mol is molar mass of the unknown</h3>
6 0
2 years ago
Scientists examine radio waves to determine the composition and structure of a newly discovered object.
Svetach [21]

Answer:

True.

Hope this helps!

let me know if u get it right

5 0
2 years ago
In the equation, 2Al (s) + 3Cl2 (g) → 2AlCl3 (s), the large number “3” in front of the Cl2 indicates:
dybincka [34]

In the equation,

2Al(s) + 3Cl2(g) —> 2AlCl3(s),

the large number "3" in front of Cl2 indicates the the number of moles of Chlorine molecules needed to balance the equation.

Hope this will help you. 

If you like my answer. Please mark it as brainliest  And  Be my follower if possible.

5 0
2 years ago
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