What symbol is used for a beta particle?

Chemistry

2 answers:

Vinvika [58]3 years ago

6 0

Answer:

The first option is correct

marin [14]3 years ago

3 0

Answer:

The answer is A

Explanation:

There are two forms of beta decay, β− decay and β+ decay, which produce electrons and positrons respectively

You might be interested in

Which of the following would be a good use for a nonmetal? handle of frying pan electrical wires structural components in buildi

lora16 [44]

Handle of frying pan would be a good use for a nonmetal. A nonmetal is neither a good thermal insulator nor a good electrical conductor. Because it is neither, it can be use as a semiconductor. It does not absorb heat that much that is why it is best in insulating.

7 0

3 years ago

Read 2 more answers

What describes the current model of an atom

vladimir2022 [97]

Answer:

A tiny sense positively charge core called a nucleus in which nearly all the mass is concentratedm

8 0

3 years ago

11C. Potassium hydrogen phthalate is a solid, monoprotic acid frequently used in the laboratory to standardize strong base solut

Llana [10]

For the reactants,

The oxidation number of hydrogen = +1
The oxidation number of oxygen = -2
The oxidation number of arsenic = +5
The oxidation number of carbon = +3

For the products,

The oxidation number of hydrogen = +1
The oxidation number of oxygen = -2
The oxidation number of arsenic = +3
The oxidation number of carbon = +4

Here, arsenic (+5 to +3) and carbon (+3 to +4) are the only oxidation numbers changing.

Note that an increase in oxidation number means electrons are lost. Thus oxidation is occurring, and a decrease in oxidation number means electrons are being gained, and thus reduction is occurring.

Also, the compound that contains the element being oxidized is the reducing agent, and the compound that contains the element being reduced is the oxidizing agent.

So, the answers are:

name of the element oxidized: Carbon

name of the element reduced: Arsenic

formula of the oxidizing agent: $\text{H}_{3}\text{AsO}_{4}$