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2 years ago

What symbol is used for a beta particle?

Chemistry

2 answers:

Vinvika [58]2 years ago

6 0

Answer:

The first option is correct

marin [14]2 years ago

3 0

Answer:

The answer is A

Explanation:

There are two forms of beta decay, β− decay and β+ decay, which produce electrons and positrons respectively

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Magnesium hydroxide [Mg(OH)2] is an ingredient in some antacids. How many grams of Mg(OH)2 are needed to neutralize the acid in

Allushta [10]

Answer:

1.95g of Mg(OH)2 are needed

Explanation:

Mg(OH)2 reacts with HCl as follows:

Mg(OH)2 + 2 HCl → MgCl2 + 2H2O

<em>Where 1 mole of Mg(OH)2 reacts with 2 moles of HCl</em>

To solve this question we must find the moles of acid. Then, with the chemical equation we can find the moles of Mg(OH)2 and its mass:

<em>Moles HCl:</em>

158mL = 0.158L * (0.106mol / L) = 0.01675 moles HCl

<em>Moles Mg(OH)2:</em>

0.01675 moles HCl * (2mol Mg(OH)2 / 1mol HCl) = 0.3350 moles Mg(OH)2

<em>Mass Mg(OH)2 -Molar mass: 58.3197g/mol-</em>

0.3350 moles Mg(OH)2 * (58.3197g / mol) =

<h3>1.95g of Mg(OH)2 are needed</h3>

3 0

3 years ago

When people walked on the Moon, they found that they could jump higher than they could back on Earth. Why is this true?

Allushta [10]

Answer: B

Explanation: the moon is smaller and contains less mass, therefore its gravitational pull is less than that of Earth's.

8 0

3 years ago

How many molecules of nitrogen gas are found in 0. 045 L of nitrogen gas at STP?

stepan [7]

Answer:

See below

Explanation:

.045 liter / 22.4 l / mole * 6.022 x 10^23 molecules/mole * 2 atoms/molecule =

( * 2 becuase nitrogen gas is diatomic)

7 0

1 year ago

What is moment and its calculations

PIT_PIT [208]

Answer:

Moment=Force x Pivot

Explanation:

A moment is the turning effect of a force. Moments act about a point in a clockwise or anticlockwise direction.

Law of moments:

When an object is balanced (in equilibrium) the sum of the clockwise moments is equal to the sum of the anticlockwise moments.

How to calculate moments:

Moment=Force x Pivot

3 0

2 years ago

A sample of O2 gas occupies a volume of 571 mL at 26 ºC. If pressure remains constant, what would be the new volume if the tempe

Vlad1618 [11]

Answer: The new volume at different given temperatures are as follows.

(a) 109.81 mL

(b) 768.65 mL

(c) 18052.38 mL

Explanation:

Given: $V_{1}$ = 571 mL, $T_{1} = 26^{o}C$

(a) $T_{2} = 5^{o}C$

The new volume is calculated as follows.

$\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}\\\frac{571 mL}{26^{o}C} = \frac{V_{2}}{5^{o}C}\\V_{2} = 109.81 mL$

(b) $T_{2} = 95^{o}F$

Convert degree Fahrenheit into degree Cesius as follows.

$(1^{o}F - 32) \times \frac{5}{9} = ^{o}C\\(95^{o}F - 32) \times \frac{5}{9} = 35^{o}C$

The new volume is calculated as follows.

$\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}\\\frac{571 mL}{26^{o}C} = \frac{V_{2}}{35^{o}C}\\V_{2} = 768.65 mL$

(c) $T_{2} = 1095 K = (1095 - 273)^{o}C = 822^{o}C$

The new volume is calculated as follows.

$\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}\\\frac{571 mL}{26^{o}C} = \frac{V_{2}}{822^{o}C}\\V_{2} = 18052.38 mL$

8 0

3 years ago