Omg! please help! it’s due in 4 hours and i don’t know the answers to it

Mathematics

1 answer:

forsale [732]3 years ago

3 0

-3 i think or -5 depending on

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6. You've just received an order of silk flower arrangements from your wholesaler. You paid $20.00 each for them. Your store use

cupoosta [38]

10% of $20 is $2 (take off the end 0)
$20+10%=?
$20+$2[this is 10%]=$22
The selling price is $22

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A giraffe's height is 5 meters 40 centimeters. <br><br> How tall is the giraffe in millimeters?

nika2105 [10]

Answer:

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Step-by-step explanation:

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3 years ago

1) Is 26,341 divisible by 3? If it is, write the number as the product of 3 and another factor. If not, explain.

yan [13]

Answer:

Step-by-step explanation:

26341 ÷ 3 = 8780.333333

because the product has a decimal of 8780 recurring 3, therefore 26341 is not divisible by 3

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3 years ago

Sketch the domain D bounded by y = x^2, y = (1/2)x^2, and y=6x. Use a change of variables with the map x = uv, y = u^2 (for u ?

cluponka [151]

Under the given transformation, the Jacobian and its determinant are

$\begin{cases}x=uv\\y=u^2\end{cases}\implies J=\begin{bmatrix}v&u\\2u&0\end{bmatrix}\implies|\det J|=2u^2$

so that

$\displaystyle\iint_D\frac{\mathrm dx\,\mathrm dy}y=\iint_{D'}\frac{2u^2}{u^2}\,\mathrm du\,\mathrm dv=2\iint_{D'}\mathrm du\,\mathrm dv$

where $D'$ is the region $D$ transformed into the $u$ - $v$ plane. The remaining integral is the twice the area of $D'$ .

Now, the integral over $D$ is

$\displaystyle\iint_D\frac{\mathrm dx\,\mathrm dy}y=\left\{\int_0^6\int_{x^2/2}^{x^2}+\int_6^{12}\int_{x^2/2}^{6x}\right\}\frac{\mathrm dx\,\mathrm dy}y$

but through the given transformation, the boundary of $D'$ is the set of equations,

$\begin{array}{l}y=x^2\implies u^2=u^2v^2\implies v^2=1\implies v=\pm1\\y=\frac{x^2}2\implies u^2=\frac{u^2v^2}2\implies v^2=2\implies v=\pm\sqrt2\\y=6x\implies u^2=6uv\implies u=6v\end{array}$

We require that $u>0$ , and the last equation tells us that we would also need $v>0$ . This means $1\le v\le\sqrt2$ and $0$ , so that the integral over $D'$ is