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Lisa [10]
3 years ago
7

Question 2.3

Chemistry
2 answers:
SVETLANKA909090 [29]3 years ago
5 0

Answer:

Your answer is :- C [OH-] = 10 x 10-7 mol dm-3

Mark this as Brainliest

Ghella [55]3 years ago
5 0

<em>Answer</em><em>:</em>

C[OH-] = 10 × 10-7 moldm-3

<em><u>Please</u></em><em><u> </u></em><em><u>mark</u></em><em><u> </u></em><em><u>as</u></em><em><u> </u></em><em><u>brainlist</u></em><em><u> </u></em><em><u> </u></em><em><u>!</u></em><em><u>!</u></em>

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2 years ago
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for the following reaction how many grams of h20 will be produced if you react 3.7 grams of B2H6? B2h6 +3O2-2hbo2+ 2 H20
Nana76 [90]

Answer:

4.8 g H₂O

Explanation:

To find the mass of water, you need to (1) convert grams B₂H₆ to moles B₂H₆ (via molar mass from periodic table), then (2) convert moles B₂H₆ to moles H₂O (via mole-to-mole ratio from reaction coefficients), and then (3) convert moles H₂O to grams H₂O (via molar mass from periodic table).

It is important to arrange the ratios/conversions in a way that allows for the cancellation of units (the desired unit should be in the numerator). The final answer should have 2 sig figs because the given value (3.7 grams) has 2 sig figs.

Molar Mass (B₂H₆): 2(10.811 g/mol) + 6(1.008 g/mol)

Molar Mass (B₂H₆): 27.67 g/mol

1 B₂H₆ + 3 O₂ ---> 2 HBO₂ + 2 H₂O
^                                             ^

Molar Mass (H₂O): 15.998 g/mol + 2(1.008 g/mol)

Molar Mass (H₂O): 18.014 g/mol

3.7 g B₂H₆          1 mole            2 moles H₂O           18.014 g
----------------  x  ---------------  x  -----------------------  x  -----------------  =  4.8 g H₂O
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6 0
2 years ago
A sample of a compound contains 160 g of oxygen and 20.2 g of hydrogen. Give the compound's empirical formula.
Maslowich
Amount of oxygen in the compound = 160 g
Amount of oxygen in the compound = 20.2 gm
Mole of oxygen in the compound = 160/16
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Mole of hydrogen in the compound = 20.2/1.01
                                                         = 20 moles
Then
The ratio of oxygen to ration of hydrogen = 1:2
So
The empirical formula of the compound is H2O. I hope the answer has come to your help.
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3 years ago
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