Answer:
In a volumetric flask of marking 500.0 mL add 138.75 grams of calcium chloride and add small amount of water to dissolve solute completely. After the solute gets completely soluble add more water up till the mark of 500 ml.
Explanation:
Concentration of calcium chloride = 2.5 M
Volume of the solution = 500.0 ml = 0.5000 L
Moles of calcium chloride = n
![c=\frac{n}{V(L)}](https://tex.z-dn.net/?f=c%3D%5Cfrac%7Bn%7D%7BV%28L%29%7D)
n = moles of solute
c = concentration of solution
V = volume of the solution in L
![2.5 M=\frac{n}{0.5000 L}](https://tex.z-dn.net/?f=2.5%20M%3D%5Cfrac%7Bn%7D%7B0.5000%20L%7D)
![n=2.5 M\times 0.5000 L = 1.2500 mol](https://tex.z-dn.net/?f=n%3D2.5%20M%5Ctimes%200.5000%20L%20%3D%201.2500%20mol)
![n=\frac{\text{Mass of calcium chloride}}{\text{Molar mass of calcium chloride}}](https://tex.z-dn.net/?f=n%3D%5Cfrac%7B%5Ctext%7BMass%20of%20calcium%20chloride%7D%7D%7B%5Ctext%7BMolar%20mass%20of%20calcium%20chloride%7D%7D)
![1.2500 mol=\frac{\text{Mass of calcium chloride}}{111 g/mol}](https://tex.z-dn.net/?f=1.2500%20mol%3D%5Cfrac%7B%5Ctext%7BMass%20of%20calcium%20chloride%7D%7D%7B111%20g%2Fmol%7D)
Mass of calcium chloride = 111 g/mol × 1.2500 mol = 138.75 g
In a volumetric flask of marking 500.0 mL add 138.75 grams of calcium chloride and add small amount of water to dissolve solute completely. After the the solute gets completely soluble add more water up till the mark of 500 ml.
Answer:
See the explanation
Explanation:
1) The Lewis structure for
has a central Carbon<em> </em>atom attached to Oxygen atoms.
In the
we will have a structure: O=C=O the <u>central atom</u> "carbon" we will have <u>2 sigma bonds and 2 pi bonds</u>, therefore, we have an <u>Sp hybridization</u>. For O we have <u>1 pi and 1 sigma bond</u>, therefore, we have an <u>Sp2 hybridization</u>.
2) These atoms are held together by <u>double bonds.</u>
<u></u>
Again in the structure of
: O=C=O we only have double bonds.
3. Carbon dioxide has a Carbon dioxide has a <u>Linear</u> electron geometry.
Due to the double bonds we have to have a linear structure because in this geometry the atoms will be further apart from each other.
4. The carbon atom is <u>Sp</u> hybridized.
We will have for carbon 2 pi bonds, so we will have an <u>Sp</u> hybridization.
5. Carbon dioxide has two Carbon dioxide has two C(p) - O(p) π bonds and two C(sp) - O(Sp2) σ bonds.
(See figures)
Figure 1: Carbon hybridization
Figure 2: Oxygen hybridization
C. is the correct answr hoping this correct and has helped you !
Answer:
The answer to your question is P2 = 84.16 kPa
Explanation:
Data
Volume 1 = V1 = 4.52 L Volume 2 = V2 = 4.83 l
Pressure 1 = P1 = 102 kPa Pressure 2 = P2 = ?
Temperature 1 = T1 = 23°C Temperature 2 = T2 = -12°C
Process
1.- Convert the temperature to °K
Temperature 1 = 23 + 273 = 296°K
Temperature 2 = -12 + 273 = 261°K
2.- Use the Combined Gas law to solve this problem
P1V1/T1 = P2V2/T2
-Solve for P2
P2 = P1V1T2 / T1V2
-Substitution
P2 = (102)(4.52)(261) / (296)(4.83)
-Simplification
P2 = 120331.44 / 1429.68
-Result
P2 = 84.16 kPa