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Vikki [24]
3 years ago
9

What is characteristic of a covalent bond?

Chemistry
1 answer:
dmitriy555 [2]3 years ago
7 0
A.electrons are shared between two different nuclei
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What is the difference between concentrated acid and a weak one?
makkiz [27]

Answer:

Difference between concentrated acid and weak acid :---

  • According to Arrhenius's theory the substances which easily get dissociated into H+ ions when dissolved in water are acids.

  • And the substance which readily gives H+ ions on dissociation (when dissolved in water) are Strong Acid. Examples are HCl , H2SO4 etc.

While,

  • Concentration of acid is just the value of pH. pH is the measurement of concentration of acid or base. The lower the pH, higher the concentration.

  • So strong acid is strong because it gives H+ ions readily in water and Concentration is the value of pH.
7 0
2 years ago
Coke is an impure form of carbon that is often used in the in- dustrial production of metals from their oxides. If a sample of c
steposvetlana [31]

Answer:

The mass of coke needed to react completely with 1.0 ton of copper(II) oxide is 0.794 Ton.

Explanation:

2CuO+C\rightarrow 2Cu+CO_2

1 Ton = 907185 grams

Mass of copper oxide = 1.0 Ton = 907185 grams

Moles of copper oxide =\frac{907185 g}{79.55 g/mol}=11,403.95 moles

According to reaction, 2 moles of copper oxide reacts with 1 mole of carbon.

Then 11403.95 moles of copper oxide will react with:

\frac{1}{2}\times 11403.95 mol=5,701.98 mol of carbon

Mass of 5,701.98 moles of carbon:

5,701.98 mol\times 12 g/mol=68,423.75 g

Mass of coke = x

Mass of carbon = 68,423.75 g

Percentage of carbon in coke = 95%

95\%=\frac{68,423.75 g}{x}\times 100

x=720,250.09 g=0.794 Ton

The mass of coke needed to react completely with 1.0 ton of copper(II) oxide is 0.794 Ton.

3 0
3 years ago
PLEASE HELP MEEE I WILL MARK BRAINLIST FOR THIS ITS SUPER SIMPLE....BUT U MUST TYPE EVERYTHING
Alina [70]

Answer:

Threatened Species: A threatened species is a species at risk but not yet endangered. California sea otters were classififed as a threatened species. Laws were passed to protect the otters and now they have increased their population size.

Invasive Species: One of the main causes of extinction and endangered species is the introduction of an exotic species. New exotic species are called invasive species. Invasive species can disrupt food chains, carry disease, prey on native species directly, and out-compete native species for limited resources, like food.

Extinction: If a population decreases too much in numbers, they disappear. Extinct species mean that the species has died out and no individuals left. An example of extinction: New Zealand was once home to a bird called the Giant Moa. Humans settled as their population increased the Moa population decreased. The species is now extinct.

Explanation:

7 0
2 years ago
Read 2 more answers
Which observation does not indicate that a chemical reaction has occurred?
castortr0y [4]

Answer:

change in the total mass of substances

6 0
3 years ago
In order to prepare 50.0 mL of 0.100 M NaOH you will add _____ mL of 1.00 M NaOH to _____ mL of water
FinnZ [79.3K]

The question requires us to complete the sentence regarding the preparation of a more dilute NaOH solution (0.100 M, 50.0 mL) from a more concentrated NaOH solution (1.00 M).

Analyzing the blank spaces that we need to fill in the sentence, we can see that we must provide the volume of the more concentrated solution and the volume of water necessary to prepare the solution.

We can use the following equation to calculate the volume of more concentrated solution required:

\begin{gathered} C_1\times V_1=C_2\times V_2 \\ V_1=\frac{C_2\times V_2}{C_1} \end{gathered}

where C1 is the concentration of the initial solution (C1 = 1.00 M), V1 is the volume required of the inital solution (that we'll calculate), C2 is the concentration of the final solution (C2 = 0.100 M) and V2 is the volume of the final solution (V2 = 50.0 mL).

Applying the values given by the question to the equation above, we'll have:

\begin{gathered} V_1=\frac{C_2\times V_2}{C_1} \\ V_1=\frac{0.100M_{}\times50.0mL_{}}{1.00M_{}}=5.00mL \end{gathered}

Thus, we would need 5.00 mL of the more concentrated solution.

Since the volume of the final solution is 50.0 mL and it corresponds to the volume of initial solution + volume of water, we can calculate the volume of water necessary as:

\begin{gathered} \text{final volume = volume of initial solution + volume of water} \\ 50.0mL=5.00mL\text{ + volume of water} \\ \text{volume of water = 45.0 mL} \end{gathered}

Thus, we would need 45.0 mL of water to prepare the solution.

Therefore, we can complete the sentence given as:

<em>"In order to prepare 50.0 mL of 0.100 M NaOH you will add </em>5.00 mL<em> of 1.00 M NaOH to </em>45.0 mL<em> of water"</em>

5 0
10 months ago
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