Answer:
Explanation:
Equation for translational kinetic energy = 1/2 m V² where m is mass and V is velocity .
In first case let mass of car be m
Translational kinetic energy = 1/2 m x 40² = 800 m .
In the second case ,
Translational kinetic energy = 1/2 m x 20² = 200 m
So , in former case kinetic energy of car is 4 times that of second case.
Something that goes round in circles could have a high speed but zero average velocity.
The result is although the wire's resistivity doesn't change, its resistance does.
Considering the formula for a material's resistance:
R=pL/A
R is directly proportional to L and inversely proportional to A, as can be seen. Be aware that "rho" is a material-specific and intensive attribute (meaning this value will not change if the material is only physically altered). Remember that A = This implies that the relationship between R and the square of r is inverse. When the wire is stretched, the impacts on length are less noticeable than the effects on r. Therefore the wire's resistance increases, but its resistivity stays the same.
Learn more about resistance here:
brainly.com/question/20708652
#SPJ4
This question is incomplete, the complete question is;
Flag
A constant force F = 6i+8j-6k moves an object along a straight line from point (6, 0, -10) to point (-6, 7, 2).
Find the work done if the distance is measured in meters and the magnitude of the force is measured in newtons.
Answer:
the work done is -88 J
Explanation:
Given the data in the question;
we know that;
Work done = F × S
where constant force F = ( 6i + 8j - 6k )
S = ( -6i + 7j + 2k ) - ( 6i + 0j - 10k )
S = ( (-6i - 6i) + (7j - 0j) + ( 2k - ( -10k) ) )
S = ( -12I + 7j + 12k )
so
Work force = ( 6i + 8j - 6k ) × ( -12I + 7j + 12k )
Work force = ( 6 × -12 ) + ( 8 × 7 ) + ( -6 × 12 )
Work force = -72 + 56 - 72
Work force = -88 J
Therefore, the work done is -88 J