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LUCKY_DIMON [66]
3 years ago
15

Igneous rocks are formed from _____.

Physics
1 answer:
Leni [432]3 years ago
7 0

Answer:

magma

Explanation:

actually cooling and solidification of magma

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Помогите плз!
Softa [21]

Все написано в скобках правильно

3 0
3 years ago
Two bodies of specific heats S1 and S2 having the same heat capacities are combined to form a single composite body. What is the
Dafna11 [192]

\qquad\qquad\huge\underline{{\sf Answer}}♨

Heat capacity of body 1 :

\qquad \sf  \dashrightarrow \:m_1s_1

Heat capacity of body 2 :

\qquad \sf  \dashrightarrow \:m_2s_2

it's given that, the the head capacities of both the objects are equal. I.e

\qquad \sf  \dashrightarrow \:m_1s_1 = m_2s_2

\qquad \sf  \dashrightarrow \:m_1 =  \dfrac{m_2s_2}{s_1}

Now, consider specific heat of composite body be s'

According to given relation :

\qquad \sf  \dashrightarrow \:(m_1 + m_2) s' = m_1s_1 + m_2s_2

\qquad \sf  \dashrightarrow \:s' = \dfrac{ m_1s_1 + m_2s_2}{m_1 + m_2}

\qquad \sf  \dashrightarrow \:s' = \dfrac{ m_2s_2+ m_2s_2}{ \frac{m_2s_2}{s_1} + m_2 }

[ since, m_2s_2 = m_1s_1 ]

\qquad \sf  \dashrightarrow \:s' = \dfrac{ 2m_2s_2}{ m_2(\frac{s_2}{s_1} + 1)}

\qquad \sf  \dashrightarrow \:s' = \dfrac{ 2 \cancel{m_2}s_2}{  \cancel{m_2}(\frac{s_2}{s_1} + 1)}

\qquad \sf  \dashrightarrow \:s' = \dfrac{ 2 s_2}{  (\frac{s_2 + s_1}{s_1} )}

\qquad \sf  \dashrightarrow \: s' =  \dfrac{2s_1s_2}{s_1 + s_2}

➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖

6 0
2 years ago
Read 2 more answers
Magnets attract objects made up of _______;_______and _______​
mixas84 [53]
I think metal, steel and copper.
3 0
2 years ago
What two factors affect the speed of a sound wave as it travels through a medium ?​
iragen [17]
The material that makes up the medium such as air or water and the temperature.
6 0
3 years ago
A metal can containing condensed mushroom soup has mass 215 g, height 10.8 cm, and diameter 6.38 cm. It is placed at rest on its
s344n2d4d5 [400]

Answer:

Part a)

Moment of inertia of the cylinder is given as

I = 1.21 \times 10^{-4} kg m^2

Part B)

Height of the cylinder is of no use here to calculate the inertia

Part C)

Since we don't know about the viscosity data of the soup inside the cylinder so we can't say directly about the moment of inertia of the cylinder as I = 1/2 mR^2

Explanation:

As we know that the inclined plane is of length L = 3 m

and its inclination is given as 25 degree

so we know that acceleration of center of mass of the cylinder is constant so we will have

v_f^2 = v_i^2 + 2 a L

so we have

v_f^2 = 0 + 2a(3)

now we know that

v_{avg} = \frac{L}{t} = \frac{v_f + v_i}{2}

\frac{3}{1.50} = \frac{v_f + 0}{2}

v_f = 4 m/s

Now we have know that final speed of the cylinder due to pure rolling is given as

v_f = \sqrt{\frac{2gH}{1 + \frac{I}{mR^2}}}

4 = \sqrt{\frac{2(9.81)(3 sin25)}{1 + \frac{I}{0.215(0.0319)^2}}}

I = 1.21 \times 10^[-4} kg m^2

Part B)

Height of the cylinder is of no use here to calculate the inertia

Part C)

Since we don't know about the viscosity data of the soup inside the cylinder so we can't say directly about the moment of inertia of the cylinder as I = 1/2 mR^2

8 0
3 years ago
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